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3 years ago

HIGH POINTS BEING AWARDED!!!

2 answers:

7 0

Hello Michael!

The term of the point where angle bisectors of a triangle meet called a circumcenter.

I hope this answer helps!

Minchanka [31]3 years ago

4 0

Answer:

circumcenter.

Step-by-step explanation:

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Furkat [3]

Answer:

D) 2, 4, 8, 16, 32

Step-by-step explanation:

We have given four sets of sequence.

And we have to find out which sequence is not an arithmetic sequence.

For this the given sequences should satisfy the value of common difference(d) and Arithmetic Progression formula.

A.P. Formula,

$T_n=a+(n-1)d$

Where $T_n$ = nth term of an A.P.

a = first term of an A.P.

n = number of terms.

d = common difference.

'd' is calculated by subtracting fist term from second term.

$d = second\ term-first\ term$

A) 4, 7, 10, 13, 16

$d = 7-4=3$

$d = 10-7=3$

Here d=3 and 5th term is 16.

So we find out the 5th term by using the formula of A.P. To check whether the sequence is in A.P. or not.

$T_5=4+(5-1)3=4+4\times\ 3=4+12=16$

Here the given sequence fulfills the condition of being in A.P.

Hence the given sequence is an arithmetic sequence.

B) 1, 2, 3, 4, 5

$d =2-1=1$

$d =3-2=1$

Here d=1 and 5th term is 5.

$T_5=1+(5-1)1=1+4=5$

Here the given sequence fulfills the condition of being in A.P.

Hence the given sequence is an arithmetic sequence.

C) 15, 9, 3, -3, -9

$d =9-15=-6$

$d =3-9=-6$

Here d=-6 and 5th term is -9.

$T_5=15+(5-1)-6=15+4\times -6=15+(-24)=-9$

Here the given sequence fulfills the condition of being in A.P.

Hence the given sequence is an arithmetic sequence.

D) 2, 4, 8, 16, 32

$d_1=4-2=2$

$d_2=8-4=4$

Here $d_1=2\ But\ d_2=4$

The common difference between the terms is not same.

In case of $d_1$ .

$T_5=2+(5-1)2=2+4\times 2=2+8=10$

In case of $d_2$ .

$T_5=2+(5-1)4=2+4\times 4=2+16=18$

Here the given sequence does not fulfills the condition of being in A.P.

Hence the given sequence is not an arithmetic sequence.

Hence the correct option is D) 2, 4, 8, 16, 32.

4 0

4 years ago

Math geometry help please show work thanks

Licemer1 [7]

<h3>Answer: Tony is correct</h3>

========================================================

Explanation:

There are number of ways to go about this, but let's pick on the sides marked in the diagram below (circled in red and blue). I picked on those sides specifically because they are on either side of the marked angles (A and Q).

They help form the proportion below, in which we'll show later on its a false statement.

AE/PQ = AB/QR

24/(14.5) = 18/(11.5)

24*11.5 = 14.5*18

270 = 261

We arrive at a false statement at the end, so the original proportion is false. Furthermore, it means the figures are <u>not</u> similar.

--------------

We could try the other way around and try to see if

AE/QR = AB/PQ

is true or not

Let's find out

24/(11.5) = 18/(14.5)

24*14.5 = 11.5*18

348 = 207

We see this is false as well. The gap is even bigger than before, so the first scenario was slightly close to having similar polygons. But neither case works perfectly. So that's why we don't have similar polygons and why Tony is correct. It's not enough to look at the angles only when dealing with polygons that have more than 3 sides. If we were just focused on triangles, then Jacenta would be correct.