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3 years ago

Which receives the most solar radiation?

Chemistry

1 answer:

Anuta_ua [19.1K]3 years ago

3 0

Answer:

Explanation:

tropical areas receives the most solar radiation because the sun's rays are nearly perpendicular to the earths surface

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How many grams of sodium hydroxide (NaOH) do you need to get rid of 3000 grams of CO2? Don't worry about sig figs for this quest

Slav-nsk [51]

Answer:

It would require 80 g of NaOH .

Explanation:

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3 years ago

Why does decreasing the volume of gas cause the pressure to increase if temperature is constant

Yuri [45]

There's less space, causing the air particles to collide with the walls of the container more frequently. Pressure is that energy caused by molecules striking a surface. Thus, compacting air molecules leads to higher pressure.

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3 years ago

odium carbonate (Na2CO3Na2CO3) is used to neutralize the sulfuric acid spill. How many kilograms of sodium carbonate must be add

Arte-miy333 [17]

Answer : The mass of sodium carbonate added to neutralize must be, $6.54\times 10^3kg$

Explanation :

First we have to calculate the moles of $H_2SO_4$ .

$\text{Moles of }H_2SO_4=\frac{\text{Mass of }H_2SO_4}{\text{Molar mass of }H_2SO_4}$

Given:

Molar mass of $H_2SO_4$ = 98 g/mole

Mass of $H_2SO_4$ = $6.05\times 10^3kg=6.05\times 10^6g$

Conversion used : (1 kg = 1000 g)

Now put all the given values in the above expression, we get:

$\text{Moles of }H_2SO_4=\frac{6.05\times 10^6g}{98g/mol}=6.17\times 10^4mol$

The moles of $H_2SO_4$ is, $6.17\times 10^4mol$

Now we have to calculate the moles of $Na_2CO_3$

The balanced neutralization reaction is:

$Na_2CO_3+H_2SO_4\rightarrow Na_2SO_4+H_2CO_3$

From the balanced chemical reaction we conclude that,

As, 1 mole of $H_2SO_4$ neutralizes 1 mole of $Na_2CO_3$

So, $6.17\times 10^4mol$ of $H_2SO_4$ neutralizes

Now we have to calculate the mass of $Na_2CO_3$

$\text{ Mass of }Na_2CO_3=\text{ Moles of }Na_2CO_3\times \text{ Molar mass of }Na_2CO_3$

Molar mass of $Na_2CO_3$ = 106 g/mole

$\text{ Mass of }Na_2CO_3=(6.17\times 10^4mol)\times (106g/mole)=6.54\times 10^6g=6.54\times 10^3kg$

Thus, the mass of sodium carbonate added to neutralize must be, $6.54\times 10^3kg$

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3 years ago

If I have 9 moles of a gas at a pressure of 8.7 atm and a volume of 18 liters, what is the temperature?

alukav5142 [94]

212K
pV=nRT.
R = 0.08206

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4 years ago

Data can be arranged in visual displays called

mojhsa [17]

Data can arranged into visual displays called graphs. There are multiple types of graphs such as bar graphs, line graphs, scatter plots, and pie charts.

hopefully this helps :)

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3 years ago