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Paraphin [41]
3 years ago
14

Add a nail in CuSO4 Sodium, the colour of CuSO4 disappears why?

Chemistry
2 answers:
Gre4nikov [31]3 years ago
5 0

The iron nail displaces the Cu from the copper sulfate solution.  This results in the color of CuSO4's disappearance. Copper is less reactive than iron.

Ugo [173]3 years ago
5 0
<h2>Answer and Explanation </h2>

Add a nail in CuSO4 Sodium, the color of CuSO4 disappears because iron (Fe) is more reactive than the copper (Cu). Hence, it replaces copper. The color of copper sulphate (CuSO4) is blue but when iron (Fe) replaces its place, it becomes iron sulphate (FeSO4) which is the light green color.

When we add an iron nail in copper sulfate solution (CuSO4) the reaction takes place between them which is as Fe+CuSO4->FeSO4+Cu. Due to more reactivity of iron, replacement happens and FeSO4 forms which is light green in color. Therefore, in this reaction color changes from blue to green.

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7 0
2 years ago
A hypothetical covalent molecule, x–y, has a dipole moment of 1.44 d and a bond length of 163 pm. calculate the partial charge o
Aneli [31]
As we know,
                                     1 D  =  3.34 × 10⁻³⁰ C.m
So,
                                     1.44 D  =  ?
Solving for 1.44 D,
                                     =  (3.34 × 10⁻³⁰ C.m × 1.44 D) ÷ 1 D
                    
                         1.44 D  =  4.80 × 10⁻³⁰ C.m

Dipole Moment 
is given as,
 
                         Dipole Moment  =  q  ×  r    
Solving for q,
                         q  =  Dipole Moment / r    ------ (1)
Where,
                         Dipole Moment  =  4.80 × 10⁻³⁰ C.m

                         r  =  163 pm  =  1.63 × 10⁻¹⁰ m

Putting values in eq. 1,

                            q  =  4.80 × 10⁻³⁰ C.m / 1.63 × 10⁻¹⁰ m

                            q  =  2.94 × 10⁻²⁰ C

As,
                            1.602 × 10⁻¹⁹ C  =  1 e⁻
So,
                             2.94 × 10⁻²⁰ C  =  X e⁻

Solving for X,

                            X  =  (2.94 × 10⁻²⁰ C × 1 e⁻) ÷ 1.602 × 10⁻¹⁹ C

                                = 0.183 e⁻

Result:
           
So one element is containing + 0.183 e⁻ while the other element is containing - 0.183 e⁻.
4 0
3 years ago
Help on question 1b please? (image attached)
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3 years ago
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jekas [21]

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Answer:

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2 years ago
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