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3 years ago

Add a nail in CuSO4 Sodium, the colour of CuSO4 disappears why?

2 answers:

5 0

The iron nail displaces the Cu from the copper sulfate solution. This results in the color of CuSO4's disappearance. Copper is less reactive than iron.

Ugo [173]3 years ago

5 0

<h2>Answer and Explanation </h2>

Add a nail in CuSO4 Sodium, the color of CuSO4 disappears because iron (Fe) is more reactive than the copper (Cu). Hence, it replaces copper. The color of copper sulphate (CuSO4) is blue but when iron (Fe) replaces its place, it becomes iron sulphate (FeSO4) which is the light green color.

When we add an iron nail in copper sulfate solution (CuSO4) the reaction takes place between them which is as Fe+CuSO4->FeSO4+Cu. Due to more reactivity of iron, replacement happens and FeSO4 forms which is light green in color. Therefore, in this reaction color changes from blue to green.

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Part A. Two containers, one at 305 K and the other at 295 K, are placed in contact with each other. 1. 1 J of heat flows from th

posledela

Answer:

0.00011 JK.

The process does NOT violate the second law of thermodynamics

Explanation:

The following parameters are given which are going to help in solving for the change in entropy of the system. The term "entropy'' simply means the degree of disorderliness of a system.

=> The temperature of container A = 305 K, the temperature of container B = 295 K and the amount of heat generated when the containers are placed in contact with each other = 1. 1 J.

The change in entropy of the hot container = -(1/305) = - 0.00328 J/K.

The change in entropy of the cold container = 1/295 = 0.00339 J/K.

Therefore, the change in the entropy of the system = - 0.00328 J/K + 0.00339 J/K = 0.00011 JK.

Note that the change in entropy of the system gives a positive value. Hence, this process does not violate the second law of thermodynamics.

The process does NOT violate the second law of thermodynamics.

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3 years ago

A 10 gram sample of H20 is sealed in a 1350 ml flask at 27°C. Given the fact that water has a vapor pressure of 26.7 mmHg at thi

Aleksandr-060686 [28]

Answer:

9.9652g of water

Explanation:

The establishment of the liquid-vapor equilibrium occurs when the vapour of water is equal to vapour pressurem 26.7 mmHg. Using gas law it is possible to know how many moles exert that pressure, thus:

n = PV / RT

Where P is pressure 26,7 mmHg (0.0351atm), V is volume (1.350L), R is gas constant (0.082 atmL/molK) and T is temperature (27°C + 273,15 = 300.15K)

Replacing:

n = 0.0351atm×1.350L / 0.082atmL/molK×300.15K

n = 1.93x10⁻³ moles of water are in gaseous phase. In grams:

1.93x10⁻³ moles × (18.01g / 1mol) = 0.0348g of water

As the initial mass of water was 10g, the mass of water that remains in liquid phase is:

10g - 0.0348g = 9.9652g of water

I hope it helps!

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3 years ago

It takes 167 s for an unknown gas to effuse through a porous wall and 99 s for the same volume of n2 gas to effuse at the same t

irakobra [83]

Answer : The molar mass of the unknown gas will be 79.7 g/mol

Explanation : To solve this question we can use graham's law;

Now we can use nitrogen as the gas number 2, which travels faster than gas 1;

So, 167 / 99 = 1.687 So the nitrogen gas is 1.687 times faster that the unknown gas 1

We can compare the rates of both the gases;

So here, Rate of gas 2 / Rate of gas 1 = $\sqrt{(molar mass 1 / molar mass 2)}$

Now, 1.687 = square root [ $\sqrt{(molar mass 1) / (28.01 g/mol N_{2})}$ ]

When we square both the sides we get;

2.845 = (molar mass 1) / (28.01 g/mol N2)

On rearranging, we get,

2.845 X (28.01 g/mol N2) = Molar mass 1

So the molar mass of unknown gas will be = 79.7 g/mol

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3 years ago

you have accidentally broken a test tube and spilled a chemical on the bench. which of the following best describes what you sho

ANEK [815]

Tell the teacher, do NOT clean it up yourself.

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2 years ago

ROY G BIV arranges the colors of the rainbow *

Elanso [62]

Answer:

Wavelengths..

Explanation:

The colors we see always go from red, which is least refracted, through orange, yellow, green, blue, indigo and violet -- Roy G Biv. The blue, indigo and violet wavelengths are refracted the most as sunlight passes through raindrops.

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3 years ago