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3 years ago

How would I answer a question if it would be like this (a= -9 and b= -4)

Mathematics

2 answers:

Reika [66]3 years ago

7 0

Answer:

712

Step-by-step explanation:

So what you do is you have to substitute -9 for a and -4 b.

7(-4)^2 +5((-9)(-4)-6)=

=7(16)+5(30)=

=112+600=

=712

zalisa [80]3 years ago

4 0

Answer:

Step-by-step explanation:

You see if A if are added you or divided by or multiply by B that’s the way how you do it

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Choose True or False for each statement.

BlackZzzverrR [31]

17372!82!. 9hhhhhh nooo

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3 years ago

The cost to purchase a song from website 1 is $0.30 per song and a $5 membership fee. To purchase a song from website 2 there is

pashok25 [27]

Answer:

I belive the answer is 20 songs.

Step-by-step explanation:

The equation you're looking for to solve this is

0.30x+5=0.20x+7

Then, you would solve for x in order to get 20.

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3 years ago

Curtis paid $80 on the vet bill for his dog. Then the vet charged him $40 more for his dog's medicine. If he now owes the vet $1

Klio2033 [76]

Answer:

He paid 80 at the start, so his starting must have been 80

Step-by-step explanation:

80+40=120...

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I hope this helps!

8 0

3 years ago

Read 2 more answers

Suppose that two openings on an appellate court bench are to be filled from current municipal court judges. The municipal court

Ksju [112]

Answer:

$(a)\dfrac{92}{117}$

$(b)\dfrac{8}{39}$

$(c)\dfrac{25}{117}$

Step-by-step explanation:

Number of Men, n(M)=24

Number of Women, n(W)=3

Total Sample, n(S)=24+3=27

Since you cannot appoint the same person twice, the probabilities are <u>without replacement.</u>

(a)Probability that both appointees are men.

$P(MM)=\dfrac{24}{27}X \dfrac{23}{26}=\dfrac{552}{702}\\=\dfrac{92}{117}$

(b)Probability that one man and one woman are appointed.

To find the probability that one man and one woman are appointed, this could happen in two ways.

A man is appointed first and a woman is appointed next.
A woman is appointed first and a man is appointed next.

P(One man and one woman are appointed) $=P(MW)+P(WM)$

$=(\dfrac{24}{27}X \dfrac{3}{26})+(\dfrac{3}{27}X \dfrac{24}{26})\\=\dfrac{72}{702}+\dfrac{72}{702}\\=\dfrac{144}{702}\\=\dfrac{8}{39}$

(c)Probability that at least one woman is appointed.

The probability that at least one woman is appointed can occur in three ways.

A man is appointed first and a woman is appointed next.
A woman is appointed first and a man is appointed next.
Two women are appointed

P(at least one woman is appointed) $=P(MW)+P(WM)+P(WW)$

$P(WW)=\dfrac{3}{27}X \dfrac{2}{26}=\dfrac{6}{702}$

In Part B, $P(MW)+P(WM)=\frac{8}{39}$

Therefore:

$P(MW)+P(WM)+P(WW)=\dfrac{8}{39}+\dfrac{6}{702}\\$P(at least one woman is appointed)=\dfrac{25}{117}$

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3 years ago

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Dafna1 [17]

Answer:

Step-by-step explanation:

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