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3 years ago

PLEASE SHOW FULL SOLUTIONS!! WILL MARK BRAINLIEST FOR THE BEST ANSWER. PLEASE HELP ME! ANYONE!!

Mathematics

1 answer:

lianna [129]3 years ago

3 0

9514 1404 393

Answer:

x² +y² = 16

Step-by-step explanation:

The diagonal of a square is √2 times the side length, so the diameter of a circumscribed circle is √2 times the diameter of an inscribed circle. Each of the two outer circles is √2 times the diameter of the one just inside it, so the outer circle is (√2)(√2) = 2 times the diameter of the inner circle.

The equation of the largest circle with radius 2·2=4 is ...

x² +y² = 16

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Answer these 10 questions for 30 points. serious answers only or report and low rating

Hunter-Best [27]

Answer:

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Step-by-step explanation:

11. A line can be defined by at least two points

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13. If two planes intersect, then they form a line at the intersection.

14. If two lines intersect, then they form a point at the intersection (not a segment).

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2 years ago

Find the dimensions of the rectangle of maximum area that can be formed from a 210-in. piece of wire. (Use decimal notation. Giv

Monica [59]

Answer:

52.500 by 52.500 inches

Step-by-step explanation:

The rectangle with maximum area will be a square. Its side length will be 1/4 the perimeter, so is 210/4 = 52.5 inches.

The figure is a 52.500 inch square. The interval of optimization is <em>closed</em>.

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3 years ago

Many elementary school students in a school district currently have ear infections. A random sample of children in two different

Marta_Voda [28]

Answer:

Step-by-step explanation:

The summary of the given data includes;

sample size for the first school $n_1$ = 42

sample size for the second school $n_2$ = 34

so 16 out of 42 i.e $x_1$ = 16 and 18 out of 34 i.e $x_2$ = 18 have ear infection.

the proportion of students with ear infection Is as follows:

$\hat p_1 = \dfrac{16}{42}$ = 0.38095

$\hat p_2 = \dfrac{18}{34}$ = 0.5294

Since this is a two tailed test , the null and the alternative hypothesis can be computed as :

$H_0 :p_1 -p_2 = 0 \\ \\ H_1 : p_1 - p_2 \neq 0$

level of significance ∝ = 0.05,

Using the table of standard normal distribution, the value of z that corresponds to the two-tailed probability 0.05 is 1.96. Thus, we will reject the null hypothesis if the value of the test statistics is less than -1.96 or more than 1.96.

The test statistics for the difference in proportion can be achieved by using a pooled sample proportion.

$\bar p = \dfrac{x_1 +x_2}{n_1 +n_2}$

$\bar p = \dfrac{16 +18}{42 +34}$

$\bar p = \dfrac{34}{76}$

$\bar p = 0.447368$

$\bar p + \bar q = 1 \\ \\ \bar q = 1 -\bar p \\ \\\bar q = 1 - 0.447368 \\ \\\bar q = 0.552632$

The pooled standard error can be computed by using the formula:

$S.E = \sqrt{ \dfrac{ \bar p \bar q}{ n_1} + \dfrac{\bar p \bar p}{n_2} }$

$S.E = \sqrt{ \dfrac{ 0.447368 * 0.552632}{ 42} + \dfrac{ 0.447368 * 0.447368}{34} }$

$S.E = \sqrt{ \dfrac{ 0.2472298726}{ 42} + \dfrac{ 0.2001381274}{34} }$

$S.E = \sqrt{ 0.01177284105}$

$S.E = 0.1085$

The test statistics is ;

$z = \dfrac{\hat p_1 - \hat p_2}{S.E}$

$z = \dfrac{0.38095- 0.5294}{0.1085}$

$z = \dfrac{-0.14845}{0.1085}$

z = - 1.368

Decision Rule: Since the test statistics is greater than the rejection region - 1.96 , we fail to reject the null hypothesis.

Conclusion: There is insufficient evidence to support the claim that a difference exists between the proportions of students who have ear infections at the two schools

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3 years ago

A triangle with an area of 45.5 cm2 has a base

FromTheMoon [43]

If you know the base and area of the triangle, you can divide the base by 2, then divide that by the area to find the height

Step 1. 14 ÷ 2 = 7

Step 2. 45.5 ÷ 7 = 6.5

Height = 6.5 cm

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3 years ago

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