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qaws [65]
3 years ago
6

Alberta has 5 shirts and 4 pants. 3 of the shirts are her favorite and 2 of the pants are her favorite. If Alberta chooses an ou

tfit in the dark, what is the probability that she picks one of her favorite shirts and on of her favorite pants?
Mathematics
1 answer:
tiny-mole [99]3 years ago
5 0

Answer:

\frac{3}{10}

Step-by-step explanation:

In probability, "AND" means "multiplication" and

"OR" means "addition".

We want the probability that she picks FAVORITE SHIRT "AND" FAVORITE PANT.

Probability that she picks favorite shirt = 3/5

Probability that she picks favorite pants = 2/4 = 1/2

Since, "AND", we "multiply" both to get:

3/5 * 1/2 = 3/10

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Answer:

Five

Step-by-step explanation:

Just look at the point where x=-6

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3 years ago
The Grand Prix Formula 1 race this weekend is in Singapore. The race consists of 61 laps around a 5.067km long track. At 225 mil
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Need the answer soon please.
eimsori [14]
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8 0
3 years ago
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If a ball is thrown into the air with a velocity of 34 ft/s, its height (in feet) after t seconds is given by y = 34t − 16t2. Fi
Finger [1]

<u>ANSWER: </u>

If a ball is thrown into the air with a velocity of 34 feet per second, then velocity of the ball after 1 second is 2 feet per second

<u>SOLUTION: </u>

Given, a ball is thrown into the air with a velocity of 34 feet per second

Initial velocity (u) = 34 feet per second

And also given a relation between displacement and time = \mathrm{y}=34 \mathrm{t}-16 \mathrm{t}^{2} --- eqn 1

We need to find the velocity when t = 1 ; v = ?

We know that, v = u + at and \mathrm{s}=\mathrm{ut}+\frac{1}{2} \mathrm{at}^{2}

where v is instantaneous velocity and u is initial velocity

a is acceleration

t is time interval  

s is displacement

using the displacement and time relation eqn (1) we get

Now, when t = 1, displacement s = 34(1) – 16(1)

\mathrm{ut}+\frac{1}{2} \mathrm{at}^{2}=34-16

34 \times 1+\frac{1}{2} \times a \times 1^{2}=18

34+\frac{a}{2}=18

\begin{array}{l}{\frac{a}{2}=18-34} \\\\ {\frac{a}{2}=-16} \\ {a=-16 \times 2} \\ {a=-32}\end{array}

here, -ve sign indicates that object is in deceleration . so acceleration is -32 ft/s

now put a value in v = u + at

v = 34 + (-32)(1)

v = 34 – 32

v = 2 ft/s

Hence, velocity of the ball after 1 second is 2 ft/s

6 0
3 years ago
Find the mean, median, mode, and range of these numbers 75,95,90,95,60,95,75,95,90<br> Plzzzzzz
Shtirlitz [24]

Answer:

<em>Mean: 85 5/9</em>

<em>Median: 90</em>

<em>Mode: 95</em>

Step-by-step explanation:

<em>~ Part I ~</em>

1. To find the mean, let us take the average of the numbers through the addition of these values divided by the number of numbers:

75 + 95 + 90 + 95 + 60 + 95 + 75 + 95 + 90/9 = 770/9 =<em> 85 5/9 (85.55.....)</em>

<em>~ Part 2 ~</em>

1. Now let us arrange these numbers from least to greatest:

75 , 95 , 90 , 95 , 60 , 95 , 75 , 95 , 90 ⇒ 60,75 , 75 , 90 , 90 , 95, 95, 95,95

3. The median of this set would now be the middle number, which, (in this case) is ⇒<em> </em><em>90</em>

<em>~ Part 3 ~</em>

1. The mode is known to be the number repeated most often, and from the previous question we see the numbers arranged in a benficial manner. Now we can straight away see that the number repeated the most is ⇒<em> 95</em>

8 0
3 years ago
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