Question
Cable company A charges $45 a month for cable plus a $18 installation fee. Cable B charges $39 a month for cable plus a $30 fee for installation. Which inequality can be used to find out when the monthly cost for Cable company A is less than Cable company B?
a)39x+30<45x+18
b) 45x+18>39x+30
c) 45x+18<39x+30
d)39x+18<45x+30
Answer:
c) 45x+18<39x+30
Step-by-step explanation:
Step 1
We have to find the Algebraic expressions for the cable companies
Cable company A charges $45 a month for cable plus a $18 installation fee.
Let the number of months be represented as x
Hence, this is represented as:
$45 × x + $18
= 45x + 18
Cable B charges $39 a month for cable plus a $30 fee for installation.
Let the number of months be represented as x
Hence, this is represented as:
$39 × x + $30
= 39x + 30
The inequality that can be used to find out when the monthly cost for Cable company A is less than Cable company B?
= Cable company A < Cable company B
= 45x + 18 < 39x + 30
Therefore option c is correct
The expression which is equivalent to 8x²√375x + 2³√3x^7 if x = 0 is; 0.
<h3>Which expression is equivalent to the expression given?</h3>
According to the task content, the expression given is; 8x²√375x + 2³√3x^7.
On this note, it follows that when x=0 is substituted into the expression; the evaluation amounts to zero, 0.
Read more evaluating expressions;
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12x^2 + x -12 I think . Good luck
Download Math-way it gives answer for those Type of questions hope this helps
1. Simple interest
2. Time spent driving
3. rate of interest
4. Time money is invested.
5. Rate of speed
6. distance
Not completely sure.
