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Stels [109]
3 years ago
14

Could anyone Help? Please

Mathematics
1 answer:
GrogVix [38]3 years ago
7 0

Answer:

a.2^(a+b+c)

b.2^(a+b+a-b)=2^(2a)or 4^a

c.2^(a+b+c)/2^(a+b)=2^(a+b+c-a-b)=2^c

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Hi, can you help me answer this question, please, thank you!
frutty [35]

Given:

mean, u = 0

standard deviation σ = 1

Let's determine the following:

(a) Probability of an outcome that is more than -1.26.

Here, we are to find: P(x > -1.26).

Apply the formula:

z=\frac{x^{\prime}-u}{\sigma}

Thus, we have:

\begin{gathered} P(x>-1.26)=\frac{-1.26-0}{1} \\  \\ P(x>-1.26)=\frac{-1.26}{1}=-1.26 \end{gathered}

Using the standard normal table, we have:

NORMSDIST(-1.26) = 0.1038

Therefore, the probability of an outcome that is more than -1.26 is 0.1038

(b) Probability of an outcome that

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Answer: (0,1)

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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