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2 years ago

Quadratics solve x^2 -12X = -9. Write the answer in three decimal points,

Mathematics

1 answer:

guajiro [1.7K]2 years ago

7 0

The answer is 11.196

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The length of a rectangular garden is 3 yards greater than the width of the garden. If the garden measures 15 yards diagonally,

aliina [53]

15 x 3= 45 so therefore 45 is the length hope that help!

4 0

2 years ago

I NEED HELP PLEASE, THANK YOU!

bixtya [17]

Answer:

$\sqrt{37}$

Step-by-step explanation:

To find the distance between a point (m, n ) and the line

Ax + By + C = 0

d = $\frac{|Am +Bn+C|}{\sqrt{A^2+B^2} }$

Here (m, n) = (6, 2) and rearranging the line

6x - y + 3 = 0 ← in general form

with A = 6, B = - 1 and C = 3 , then

d = $\frac{|6(6)-1(2)+3|}{\sqrt{6^2+(-1)^2} }$

= $\frac{|36-2+3|}{\sqrt{36+1} }$

= $\frac{37}{\sqrt{37} }$

Rationalise the denominator by multiplying numerator/ denominator by $\sqrt{37}$

= $\frac{37}{\sqrt{37} }$ × $\frac{\sqrt{37} }{\sqrt{37} }$

= $\frac{37\sqrt{37} }{37}$ ← cancel 37 on numerator/ denominator

= $\sqrt{37}$

5 0

2 years ago

Read 2 more answers

x2y - 2xy - 24y = y(x2 - 2x - 24) What is the completely factored form of x2y – 2xy – 24y? (xy + 4)(x – 6) xy(x + 4)(x – 6) y(x

likoan [24]

we are given

$x^2y-2xy-24y=y(x^2-2x-24)$

now, we can factor out right side term

$x^2-2x-24=x^2-6x+4x-6*4$

$x^2-2x-24=(x-6)(x+4)$

now, we can plug back

and we get

so,

$x^2y-2xy-24y=y(x-6)(x+4)$ .............Answer

5 0

2 years ago

Read 2 more answers

The answer is C that’s why it has a 1 pt in front <br><br> Plz just help me explain how to get that

Ierofanga [76]

First lets get the formula for a triangular prism

$v =( \frac{1}{2} bh)h$

First lets plug in our numbers

$v =( \frac{1}{2} \times 7 \times 4)8.5$

It really doesnt matter how you multiply everything, but you end up with 119cubic feet.

3 0

3 years ago

He length of a rectangle is three times its width. The perimeter of the rectangle is at most 112 cm.

g100num [7]

The equation relating length to width
L = 3W
The inequality stating the boundaries of the perimeter
LW <= 112
When you plug in what L equals in the first equation into the second equation, you get
3W * W <= 112
evaluate
3W^2 <= 112
3W <= $4 \sqrt{7}$
W <= $\frac{4 \sqrt{7} }{3}$ cm

8 0

3 years ago

Read 2 more answers