To determine an nth term of an arithmetic sequence, we use the expression an = a1 + (n-1)d where a1 is the first term in the sequence, n is the number of the term in the sequence and d is the common difference. For a geometric sequence, it is expressed an = a1r^(n-1). We calculate as follows:
1. a128 = 9 + (128-1)(-5)
a128 = -626
2. a97 = (-3)(-2)^(97-1)
a97 = -2.377x10^29
Answer:
kkkk74
Step-by-step explanation:
The answer is x= 4 and x= -6
Answer:
which p? there isn't any p in above equation
