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S_A_V [24]
4 years ago
10

I need help with number 17. I have no idea what I’m doing!

Mathematics
1 answer:
kakasveta [241]4 years ago
7 0

is there anther way you can put the pic i cant see

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( please help me) ( 11 points)
lara [203]

Answer:

500cm2

Step-by-step explanation:

2(9×20)+(7×20)

=360+140=500cm2

5 0
3 years ago
tickets to a science Exposition cost $5.75 each for studentd and $7.00 for adults.How many students and adults went if the ticke
Tju [1.3M]
5*5.75 + 2*7.00 = 42.75
3 0
3 years ago
Y-12=4y solve for y and show work plz
Katena32 [7]
First, you want to start by subtracting y from each side to get it isolated. After that, your equation should be
3y= -12
Then, divide each side by 3 to isolate the y. You should end up with y= -4
7 0
3 years ago
Read 2 more answers
If the length of a rectangle is 27 feet and the perimeter is 116, what is the width?
Kobotan [32]

Answer:

w=31 feet

Step-by-step explanation:

multiply the length that you have been given by 2, and subtract the result from the perimeter. You now have the total length for the remaining 2 sides. This number divided by 2 is the width.

6 0
3 years ago
Read 2 more answers
Inequality to x2 < 64
Anarel [89]
              NOT MY WORDS TAKEN FROM A SOURCE!

(x^2) <64  => (x^2) -64 < 64-64 => (x^2) - 64 < 0 64= 8^2    so    (x^2) - (8^2) < 0  To solve the inequality we first find the roots (values of x that make (x^2) - (8^2) = 0 ) Note that if we can express (x^2) - (y^2) as (x-y)* (x+y)  You can work backwards and verify this is true. so let's set (x^2) - (8^2)  equal to zero to find the roots: (x^2) - (8^2) = 0   => (x-8)*(x+8) = 0       if x-8 = 0 => x=8      and if x+8 = 0 => x=-8 So x= +/-8 are the roots of x^2) - (8^2)Now you need to pick any x values less than -8 (the smaller root) , one x value between -8 and +8 (the two roots), and one x value greater than 8 (the greater root) and see if the sign is positive or negative. 1) Let's pick -10 (which is smaller than -8). If x=-10, then (x^2) - (8^2) = 100-64 = 36>0  so it is positive
2) Let's pick 0 (which is greater than -8, larger than 8). If x=0, then (x^2) - (8^2) = 0-64 = -64 <0  so it is negative3) Let's pick +10 (which is greater than 10). If x=-10, then (x^2) - (8^2) = 100-64 = 36>0  so it is positive Since we are interested in (x^2) - 64 < 0, then x should be between -8 and positive 8. So  -8<x<8 Note: If you choose any number outside this range for x, and square it it will be greater than 64 and so it is not valid.

Hope this helped!

:)
7 0
3 years ago
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