The derivative of f(x) at x=3 is 2x=6 approaching from the left side (apply power rule to y=x^2). The derivative of f(x) at x=3 is m approaching from the right side. In order for the function to be differentiable, the limit of derivative at x=3 must be the same approaching from both sides, so m=6. Then, x^2=mx+b at x=3, plug in m=6, 9=18+b, so b=-9.
Answer:
Value of f (Parapedicular) = 7√6
Step-by-step explanation:
Given:
Given triangle is a right angle triangle
Value of base = 7√2
Angle made by base and hypotenuse = 60°
Find:
Value of f (Parapedicular)
Computation:
Using trigonometry application
Tanθ = Parapedicular / Base
Tan60 = Parapedicular / 7√2
√3 = Parapedicular / 7√2
Value of f (Parapedicular) = 7√2 x √3
Value of f (Parapedicular) = 7√6
For (h+g)(x) you just add the two functions:
(h+g)(x) = 4x + 2x^2
For (h•g)(x) you multiply them:
(h•g)(x) = 4x • 2x^2 = 8x^3
For (h-g)(x) you subtract them:
(h-g)(x) = 4x - 2x^2
For (h-g)(-2) you sub -2 into the equation we just created:
(h-g)(-2) = 4(-2) - 2(-2)^2
(h-g)(-2) = -8 - 2(4)
(h-g)(-2) = -8 - 8
(h-g)(-2) = -16
Answer:
<h2>11.f(x)=^2-3</h2>
Step-by-step explanation:
<h2>12.And slide everything five units down. So a over here that's negative three negative one. So if we slide at five you just down we go one two three four five and get here.</h2>
Hope it helps
