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deff fn [24]
2 years ago
14

Help please!! I have no idea what I’m doing

Mathematics
1 answer:
Inga [223]2 years ago
8 0
It’s a black picture can’t see
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15x + 2x can be written as _____.<br> x(15 + 2x)<br> (15 + 2)x<br> (15x + 2x)x
Triss [41]
2x+15x you can just switch the two.
6 0
3 years ago
Read 2 more answers
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Zolol [24]

Answer:

2) Yes

3) No

4) Yes

5) 2x + 8

6) 5(x - 8)

7) 3x + 21

Hope this helps :)

5 0
2 years ago
How do you multiple the following (x-8)(x-7)
OLEGan [10]
You would need to cross multiply.  When you do that you get x^2-7x-8x+56.  Once simplifying you get x^2-15x+56.
3 0
3 years ago
Twice the difference of a number and 9 equals 8
ladessa [460]

Answer:

13 is the number.

Step-by-step explanation:

Given:

Twice the difference of a number and 9 equals 8.

Let the unknown number be 'x'.

Therefore, as per question:

The difference of 'x' and 9 = x-9

Twice the difference means 2 times the difference. So, we multiply 2 to the difference. Therefore,

2(x-9)

Now, the above expression is equal to 8. So, we equate the above expression to 8. This gives,

2(x-9)=8

Solving for 'x', we get:

Using distributive property of addition and distributing 2 inside the bracket. This gives,

2\times x-2\times 9=8\\\\2x-18=8\\\\2x=8+18\\\\2x=26\\\\x=\frac{26}{2}=13

Therefore, the unknown number is 13.

Now, we can verify our answer.

2(13-9)=26-18=8

Therefore, the answer is correct.

3 0
3 years ago
Alyze the following special produ
Eddi Din [679]

Answer:

1) Solving the term (3x + 5)(2x - 3) using F.O.I.L we get \mathbf{6x^2+x-15}

2) solving the term (x + 2)(x - 13) using F.O.I.L we get \mathbf{x^2-11x-26}

3) Solving (x+5)^2 using square of binomial we get \mathbf{x^2+10x+25}

4) Solving (x+5)^2 using square of binomial we get \mathbf{x^2-6x+9}

Step-by-step explanation:

1) (3x + 5)(2x - 3). Solve using the F.O.I.L.

F.O.I.L stands for First, Outer Inner Last

We have (3x + 5)(2x - 3)

First: 3x(2x)

Outer: 3x(-3)

Inner: 5(2x)

Last: 5(-3)

Solving we get:

(3x + 5)(2x - 3)\\=3x(2x)+3x(-3)+5(2x)+5(-3)\\=6x^2-9x+10x-15\\=6x^2+x-15

So, solving the term (3x + 5)(2x - 3) using F.O.I.L we get \mathbf{6x^2+x-15}

2) (x + 2)(x – 13). Solve using the F.O.I.L.

F.O.I.L stands for First, Outer Inner Last

We have (x + 2)(x -13)

First: x(x)

Outer: x(-13)

Inner: 2(x)

Last: 2(-13)

Solving we get:

(x + 2)(x - 13)\\=x(x)+x(-13)+2(x)+2(-13)\\=x^2-13x+2x-26\\=x^2-11x-26

So, solving the term (x + 2)(x - 13) using F.O.I.L we get \mathbf{x^2-11x-26}

3) (x + 5)^2. Solve using the square of Binomial.

The square of binomial is: (a+b)^2=a^2+2ab+b^2

Solving:

(x+5)^2\\=(x)^2+2(x)(5)+(5)^2\\=x^2+10x+25

So, solving (x+5)^2 using square of binomial we get \mathbf{x^2+10x+25}

4) (x -3)^2. Solve using the square of Binomial.

The square of binomial used is: (a-b)^2=a^2-2ab+b^2

Solving:

(x-3)^2\\=(x)^2-2(x)(3)+(3)^2\\=x^2-6x+9

So, solving (x+5)^2 using square of binomial we get \mathbf{x^2-6x+9}

5 0
2 years ago
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