What is the equation of the line that passes through the points ( 5,-2) and (-5,0)

AC = 3x -8, BC = -7 + 2x, and AB = 8.<br> Find BC.

Rainbow [258]

Answer:

AB+BC+AC=180°

8 - 7 + 2x +3x -8= 180°

-7+5x=180°

x=180°+7/5

x=37.4°

again

BC=-7+2*37.4

=67.8°

4 0

1 year ago

Anyone know how to solve this?

yuradex [85]

Answer:

Step-by-step explanation:

<h3> $( - \frac{4}{5})^{2}$ </h3><h3> ${( - 1)}^{2} \frac{ {4}^{2} }{ {5}^{2} }$ </h3><h3> $1 \frac{ {4}^{2} }{ {5}^{2} }$ </h3><h3> $\frac{ {4}^{2} }{ {5}^{2} }$ </h3><h3> $\frac{16}{25}$ </h3><h3>Hope it is helpful....</h3>

5 0

3 years ago

1. What values of a, b, and c would you use in the quadratic formula for the following equation?

Archy [21]

Question (1):
The general formula of the quadratic equation is:
ax² + bx + c = 0
The given equation is:
5x² + 9x = 4
Rearrange the given equation to look the standard one:
5x² + 9x - 4 = 0
Now, compare the coefficients in the given equation with the standard one, you will find that:
a = 5, b = 9 and c = -4

Question (2):
The given expression is:
-5 + 2x²<span> = -6x
</span>Rearrange this expression to be in standard form:
2x² + 6x - 5 = 0
This means that:
a = 2
b = 6
c = -5
The roots of the equation can be found using the formula in the attached image.
Substituting in this formula with the given a, b and c, we would find that the correct choice is third one (I have attached the correct choice)

Question (3):
Quadratic formula (the one used in the previous question, also shown in attached images) is the best method to get the solution of any quadratic equation. This is because, putting the equation in standard form, we can simply get the values of a, b and c, substitute in the formula and get the precise solutions of the equation.

Hope this helps :)

8 0

2 years ago

Read 2 more answers

App 19.study

lions [1.4K]

Answer:

$1 \to 22 \to 0.176$

$2 \to 13 \to 0.104$

$3 \to 18 \to 0.144$

$4 \to 29 \to 0.232$

$5 \to 37 \to 0.296$

$6 \to 6 \to 0.048$

Step-by-step explanation:

Given

$n = 125$

See attachment for proper table

Required

Complete the table

Experimental probability is calculated as:

$Pr = \frac{Frequency}{n}$

We use the above formula when the frequency is known.

For result of roll 2, 4 and 6

The frequencies are 13, 29 and 6, respectively

So, we have:

$Pr(2) = \frac{13}{125} = 0.104$

$Pr(4) = \frac{29}{125} = 0.232$

$Pr(6) = \frac{6}{125} = 0.048$

When the frequency is to be calculated, we use:

$Pr = \frac{Frequency}{n}$

$Frequency = n * Pr$

For result of roll 3 and 5

The probabilities are 0.144 and 0.296, respectively

So, we have:

$Frequency(3) = 125 * 0.144 = 18$

$Frequency(5) = 125 * 0.296 = 37$

For roll of 1 where the frequency and the probability are not known, we use:

$Total \ Frequency = 125$

So:

Frequency(1) added to others must equal 125

This gives:

$Frequency(1) + 13 + 18 + 29 + 37 + 6 = 125$

$Frequency(1) + 103 = 125$

Collect like terms

$Frequency(1) =- 103 + 125$

$Frequency(1) =22$

The probability is then calculated as:

$Pr(1) = \frac{22}{125}$

$Pr(1) = 0.176$

So, the complete table is:

$1 \to 22 \to 0.176$

$2 \to 13 \to 0.104$

$3 \to 18 \to 0.144$

$4 \to 29 \to 0.232$

$5 \to 37 \to 0.296$

$6 \to 6 \to 0.048$

5 0

2 years ago

HELP PLEASEE!!! I just need help with the 2 boxes

Soloha48 [4]

Answer:

$y= x - 300$

$y = -246$ -- Her equivalent weight on earth

Step-by-step explanation:

Given

The attached table

Required

Fill in the gaps

(a) The equation

First, we calculate the slope (m)

$m = \frac{y_2 - y_1}{x_2 - x_1}$

From the table, we can say that:

$(x_1,y_1) = (0,-300)$

$(x_2,y_2) = (300,0)$

So, we have:

$m = \frac{0 -(-300)}{300 - 0}$

$m = \frac{0 +300}{300}$

$m = \frac{300}{300}$

$m = 1$

The equation is then calculated using:

$y - y_1 = m(x - x_1)$

This gives:

$y - (-300) = 1(x - 0)$

$y +300 = 1(x)$

$y +300 = x$

$y= x - 300$

(b) When x = 54

Substitute 54 for x in $y= x - 300$

$y = 54 - 300$

$y = -246$

3 0

3 years ago