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3 years ago

Doobs please helpp, mah hw is too hard :,(, the question is: add the polynomial expressions using the horizontal format

Mathematics

1 answer:

Salsk061 [2.6K]3 years ago

5 0

Answer:

9s^3 + 13s

Step-by-step explanation:

Combine like terms and simplify.

(6s^3 + 3s^3) + (9s + 4s) + (10 - 10)

(9s^3) + (13s)

9s^3 + 13s

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Solve the following system of equations <br> Y= -2x – 3<br> 4y + x =16

Aleksandr-060686 [28]

Answer:

(-4,5)

*View attached graph*

Step-by-step explanation:

y = -2x - 3

4y + x = 16

4(-2x - 3) + x = 16

-8x - 12 + x = 16

-7x - 12 = 16

+12 + 12

-7x = 28

/-7 /-7

x = -4

4y + x = 16

4y + (-4) = 16

4y - 4 = 16

+ 4 + 4

4y = 20

/4 /4

y = 5

(x,y) -> (-4,5)

Hope this helps!

6 0

3 years ago

Here is the velocity-time graph of a car for 40 seconds. Work out the average acceleration during the 40 seconds

Rashid [163]

i think it will be 140 soconds

3 0

4 years ago

PLEASE HELP ASAP WILL MARK BRAINLIEST

luda_lava [24]

Answer:

x=11

Step-by-step explanation:

7x-9-4(x-1)=28

7x-9-4x+4=28

3x-5=28

3x=33

x=11

4 0

3 years ago

Find the value of a in the diagram of the right triangle 27° 11 in

tensa zangetsu [6.8K]

Sin 27=11/a
a=11/sin 27
a=24.2

5 0

3 years ago

Water is drained out of tank, shaped as an inverted right circular cone that has a radius of 4cm and a height of 16cm, at the ra

bearhunter [10]

Answer:

$\frac{dh}{dt}=-\frac{1}{2\pi}cm/min$

Step-by-step explanation:

From similar triangles, see diagram in attachment

$\frac{r}{4}=\frac{h}{16}$

We solve for $r$ to obtain,

$r=\frac{h}{4}$

The formula for calculating the volume of a cone is

$V=\frac{1}{3}\pi r^2h$

We substitute the value of $r=\frac{h}{4}$ to obtain,

$V=\frac{1}{3}\pi (\frac{h}{4})^2h$

This implies that,

$V=\frac{1}{48}\pi h^3$

We now differentiate both sides with respect to $t$ to get,

$\frac{dV}{dt}=\frac{\pi}{16}h^2 \frac{dh}{dt}$

We were given that water is drained out of the tank at a rate of $2cm^3/min$

This implies that $\frac{dV}{dt}=-2cm^3/min$ .

Since we want to determine the rate at which the depth of the water is changing at the instance when the water in the tank is 8cm deep, it means $h=8cm$ .

We substitute this values to obtain,

$-2=\frac{\pi}{16}(8)^2 \frac{dh}{dt}$

$\Rightarrow -2=4\pi \frac{dh}{dt}$

$\Rightarrow -1=2\pi \frac{dh}{dt}$

$\frac{dh}{dt}=-\frac{1}{2\pi}$

3 0

4 years ago

Read 2 more answers