<h3>
Answer: 42</h3>
Explanation:
We have y = -0.9x^2 + 76x - 250 which is in the form y = ax^2+bx+c
where,
The vertex (h,k) is when the profit is maxed out.
h = -b/(2a)
h = -76/(2(-0.9))
h = 42.222 approximately
Let's plug in x values around x = 42
Try x = 41
y = -0.9x^2 + 76x - 250
y = -0.9(41)^2 + 76(41) - 250
y = 1353.10
Now try x = 42
y = -0.9x^2 + 76x - 250
y = -0.9(42)^2 + 76(42) - 250
y = 1354.4
Now try x = 43
y = -0.9x^2 + 76x - 250
y = -0.9(43)^2 + 76(43) - 250
y = 1353.9
We see that the largest profit happens when x = 42.
Answer:
no answer. Because 8-4 is not equal to 12
Step-by-step explanation:
Answer:
d
Step-by-step explanation:
because it says that panthers are endangered
Answer:
Lola was in lead for
of a mile.
Step-by-step explanation:
We have been given that Lola and Brandon had a running race. They ran 3/10 of a mile. Lola was in the lead for 4/5 of the distance.
To find the fraction of a mile for which Lola was in the lead, we need to find 4/5 of 3/10 as:




Therefore, Lola was in lead for
of a mile.