PLEASE PLEASE HURRY!!!!!!!

19. Rae supervises a loading dock. She

Rina8888 [55]

Answer:

85% of the job is finished.

Step-by-step explanation:

The way to find the percentage is to divide 119 by 140, which will come out to be .85.

Multiply .85 by 10 to have it as a whole number for the percentage.

5 0

3 years ago

Please Help! Its due in 2 hours!

WITCHER [35]

Answer:

x=40

Step-by-step explanation:

<h3> firstly 180 -110 = 70 (sumnof angle of a straight line ) </h3><h3>180 -110 = 70 (sumnof angle of a straight line ) also the triangle is an isocelels triangle of which the two sides have equal angle </h3><h3>180 -110 = 70 (sumnof angle of a straight line ) also the triangle is an isocelels triangle of which the two sides have equal angle there fore 70 +70 +x= 180 </h3><h3>180 -110 = 70 (sumnof angle of a straight line ) also the triangle is an isocelels triangle of which the two sides have equal angle there fore 70 +70 +x= 180 140+x=180 sum of angles of a triangle </h3><h3>180 -110 = 70 (sumnof angle of a straight line ) also the triangle is an isocelels triangle of which the two sides have equal angle there fore 70 +70 +x= 180 140+x=180 sum of angles of a triangle x=180 -140 = 40 </h3>

6 0

2 years ago

BRAINLIEST AND 20 POINTS

zhannawk [14.2K]

E would be (-8,4), F would be (16,-8) and G would be (-24,-16). This is the correct answer. I hope this helps.

6 0

3 years ago

Read 2 more answers

(1st pic) What is the equation of the line shown in this graph?

vredina [299]

Answer:

For figure 1: The equation of a line is y=1

For figure 2: The equation of a line is y=(-4)x+1

For figure 3:The equation of a line is y= $\frac{-5}{2}x+5$

Step-by-step explanation:

The equation of line slope-intercept form is given by y=mx+c

Where m is the slope of the line and c is the y-intercept.

For figure 1:

Here, Line is parallel to x-axis

Hence, Slope m=0

Also, Line passing to y axis at (0,1)

Y-intercept is c=1

Therefore,

The equation of line is

y=0x+1

y=1

For figure 2:

Figure show a line passing through point (1,-3) and (-1,5)

The slope of the line is given by m= $\frac{Y2-Y1}{X2-X1}$

Using given points to find out the slope of a line

m= $\frac{Y2-Y1}{X2-X1}$

m= $\frac{5-(-3)}{(-1)-1}$

m= $\frac{8}{-2}$

m=(-4)

Also, Line is intersecting y-axis at (0,1)

Hence, c=1

We can write the equation of line as

y=mx+c

y=(-4)x+1

Thus, The correct option is D). y=(-4)x+1

For figure 3:

From the figure, a line is passing through points (-2,0) and (0,5)

The slope of the line is given by m= $\frac{Y2-Y1}{X2-X1}$

Using given points to find out the slope of a line

m= $\frac{Y2-Y1}{X2-X1}$

m= $\frac{5-0}{0-(-2)}$

m= $\frac{-5}{2}$

Also, Line is intersecting y-axis at (0,5)

Hence, c=5

We can write the equation of line as

y=mx+c

y= $\frac{-5}{2}x+5$

4 0

3 years ago

If x+a is a factor of 2x²+2ax+5x+10,find a.

vazorg [7]

If $x+a$ is a factor of the polynomial, it means that $-a$ is a root of the polynomial.

In fact, if a polynomial $p(x)$ has a root $x_0$ (i.e. $p(x_0)=0$ ), then the polynomial is divisible by $(x-x_0)$

In your case, you know that the polynomial is divisible by $(x+a)=(x-(-a))$ , so $-a$ is a solution.

Let's evaluate $p(-a)$ and set it to zero:

$2(-a)^2+2a(-a)+5(-a)+10 = 0 \iff 2a^2-2a^2-5a+10=0 \iff -5a+10 = 0 \iff a = 2$

We can check the answer: if $a=2$ the polynomial becomes

$2x^2+2(2)x+5x+10 = 2x^2+9x+10$

And we're claiming that $-a=-2$ is a root of this polynomial:

$2(-2)^2+9(-2)+10 = 2\cdot 4 - 18 + 10 = 0$

5 0

3 years ago