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Ira Lisetskai [31]
3 years ago
14

Two whole numbers have a least common multiple of 30.

Mathematics
1 answer:
Makovka662 [10]3 years ago
3 0
Yes it is 3, and 10 : )
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Find the area of the region under the graph of f on [a, b].<br> f(x) = x2 − 8x + 17; [−1, 2]
Harman [31]

Answer:

The area is 42 area units.

Step-by-step explanation:

The area of a function f(x) on an interval [a,b] is given by:

A = \int\limits^a_b {f(x)} \, dx

Applying to this question:

A = \int\limits^-1_2 {x^2 - 8x + 17} \, dx

Then

F(x) = \frac{x^{3}}{3} - 4x^{2} + 17x

A = F(2) - F(-1)

F(2) = frac{2^{3}}{3} - 4*2^{2} + 17*2 = \frac{8}{3} + 18 = \frac{8 + 3*18}{3} = \frac{62}[3}

F(-1) = frac{(-1)^{3}}{3} - 4*(-1)^{2} + 17*(-1) = -\frac{1}{3} - 21 = \frac{-1 - 21*3}{3} = -\frac{64}[3}

A = F(2) - F(-1) = \frac{62}[3} - (-\frac{64}[3}) = \frac{62+64}{3} = 42

The area is 42 area units.

5 0
3 years ago
Solve for r.<br><br> r - 4.5 ≤ 11
erma4kov [3.2K]

Answer:

The answer is r < or equal to 15.5.

Step-by-step explanation:

3 0
2 years ago
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How to factor this equation
KIM [24]

Answer:

Step-by-step explanation:

x2=256

By taking Square root we get

x=16

7 0
3 years ago
The product of two consecutive positive integers is 56. Find the two integers
vredina [299]

Answer:

Two consecutive integers are of the form

x and x + 1

Their product is equal to 56

x(x + 1) = 56

Solve and find the two numbers x and x + 1. The above equation may be written as follows

x2 + x - 56 = 0

Factor and solve

(x - 7)(x + 8) = 0

solutions: x = 7 , x = -8

x= - 8 is not valid since the number sought must be positive. Hence

x = 7 and x + 1 = 8 are the two consecutive numbers.

Step-by-step explanation:

7 0
3 years ago
1. Rich wants to buy a coat priced at x dollars. It is on sale for 20% off. He must
alexandr1967 [171]

Answer: x-0.20x+0.0725x

Step-by-step explanation:

Let x be the price. 20% (0.20) 7.25% (0.0725)

x-0.20x+0.0725x

6 0
3 years ago
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