Please help. :( need a real mathematics wizz to help me.

Mathematics

2 answers:

natali 33 [55]2 years ago

6 0

Answer:

£65.10

Step-by-step explanation:

42*8 = 336

10% = 33.6

14*15 = 210

10% = 21

5% = 10.5

31.5 +33.6 = £65.10

hope this is correct ^^

Ratling [72]2 years ago

4 0

The is is 65.10.........

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Mabel is comparing the prices of two car rental companies. Company A charges $35 per day and an additional $15 as service charge

patriot [66]

Company A : C = 35D + 15....C is total cost and D is number of days
company B : C = 42D + 10...C is total cost and D is number of days
================
which company charges less for renting for 6 days
company A :
C = 35(6) + 15 = 225

company B :
C = 42(6) + 10 = 262

so company A charges less when renting for 6 days
=================
for 10 days...
company A :
C = 35(10) + 15 = 365

company B :
C = 42(10) + 10 = 430

so there would be (430 - 365) = 65 saved when using company A instead of company B

4 0

3 years ago

Suppose an airline accepted 12 reservations for a commuter plane with 10seats. They know that 7 reservations went to regular com

kvv77 [185]

Answer:

<h2>See the explanation.</h2>

Step-by-step explanation:

(a)

7 persons will show up for sure, hence there is not any kind of probability here.

The other 5 persons have 50% chance to show up.

The flight will be overbooked, if either 4 will come or 5 will come.

From the total 5 persons, 4 can be chosen in $^5C_4 = 5$ ways.

The probability that any four among the 5 will come is $5\times(\frac{50}{100} )^{5} = 5\times(\frac{1}{2} )^{5} = \frac{5}{32}$ .

The probability that all of the 5 passengers will come is $\frac{1}{32}$ .

Hence, the required probability is $\frac{5}{32} + \frac{1}{32} = \frac{6}{32} = \frac{3}{16}$ .

(b)

The probability that there will be exactly 10 passengers on the flight is $^5C_3\times (\frac{1}{2} )^5 = \frac{20}{2} \times\frac{1}{32} = \frac{10}{32} = \frac{5}{16}$ .