If restaurant served 517 meals at lunch. It then served 257 meals at dinner. How many meals did it serve in all
1 answer:
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First, we are going to want to see if there are any terms we can simplify. By examining the numerators and denominators of our functions, we can see that we can remove a 3 from the denominator of the second function and the numerator of the first function. This would be represented as:
Now, we can multiply the fractions. Remember that to multiply fractions, simply multiply both the numerators over both the denominators, as shown below:
By applying this information, we can solve for the product of the fractions:
Our answer is .
<span>An extraneous solution is a solution, such as that to an equation, that emerges from the process of solving the problem but is not a valid solution to the original problem.
Given the equation:
From the equation, it is obtained that x = 1 and x = -4 are the solutions of the equation.
Now, we substitute x = 1 into the equation as follows:
</span><span>
As can be see, for x = 1, the equation is undefined.
Now, we substitute x = -4 into the equation as follows:
It can be seen that x = -4 is a valid solution of the orignal equation.
Therefore, x = 1 is an extraneous solution to the equation
</span>
Given the equation:
From the equation, it is obtained that x = 1 and x = -4 are the solutions of the equation.
Now, we substitute x = 1 into the equation as follows:
</span><span>
As can be see, for x = 1, the equation is undefined.
Now, we substitute x = -4 into the equation as follows:
It can be seen that x = -4 is a valid solution of the orignal equation.
Therefore, x = 1 is an extraneous solution to the equation