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3 years ago

This is the question

Mathematics

2 answers:

DENIUS [597]3 years ago

8 0

Answer:

A

Step-by-step explanation:

As the hours increase by 1, the distance traveled increases by 50.

erastovalidia [21]3 years ago

8 0

Answer: answer is A

Step-by-step explanation:

Both sides increase.

The hours go by one and the distance goes by 50

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NEED HELP IMAGE ATTACHED!!!

masha68 [24]

Answer:

$\frac{ {7x}^{2} - 5x + 1}{4x + 1}$

Step-by-step explanation:

Since the denominators are the same we just have to combine the top.

${x}^{2} - 5x + {6x}^{2} + 1$

Combine alike terms.

${7x}^{2} - 5x + 1$

put that over our denominator.

$\frac{ {7x}^{2} - 5x + 1 }{4x + 1}$

6 0

3 years ago

What can you conclude from the following true statements?

lys-0071 [83]

There is snow on the ground outside.

3 0

3 years ago

Solve each equation. I don't know this

MArishka [77]

1. $(2x - 3)(x + 7) = 0$
 $2x^{2} + 14x - 3x - 21 = 0$
 $2x^{2} + 11x - 21 = 0$

 $x = \frac{-11 +/- \sqrt{11^{2} - 4(2)(-21)}}{2(2)}$

 $x = \frac{-11 +/- \sqrt{121 + 168}}{4}$

 $x = \frac{-11 +/- \sqrt{289}}{4}$

 $x = \frac{-11 +/- 17}{4}$

 $x = -2.75 +/- 4.25$
 $x = -2.75 + 4.25$ $x = -2.75 - 4.25$
 $x = 1.5$ $x = -7$
---------------------------------------------------------------------------------------------------------- 2. $8x(2x - 5) = 0$
 $8x(2x) - 8x(5) = 0$
 $16x^{2} - 40x = 0$
 $16x^{2} - 4x + 0 = 0$

 $x = \frac{-(-40) +/- \sqrt{(-40)^{2} - 4(16)(0)}}{2(16)}$

 $x = \frac{40 +/- \sqrt{1600 - 0}}{32}$

 $x = \frac{40 +/- \sqrt{1600}}{32}$

 $x = \frac{40 +/- 40}{32}$

 $x = 1.25 +/- 1.25$
 $x = 1.25 + 1.25$ $x = 1.25 - 1.25$
 $x = 2.5$ $x = 0$
----------------------------------------------------------------------------------------------------------
3. $x^{2} + 3x - 10 = 0$

 $x = \frac{-3 +/- \sqrt{3^{2} - 4(1)(-10)}}{2(1)}$

 $x = \frac{-3 +/- \sqrt{9 + 40}}{2}$

 $x = \frac{-3 +/- \sqrt{49}}{2}$

 $x = \frac{-3 +/- {7}}{2}$

 $x = -1.5 +/- 3.5$
 $x = -1.5 + 3.5$ $x = -1.5 - 3.5$
 $x = 2$ $x = -5$
----------------------------------------------------------------------------------------------------------
4. $x^{2} = 13x - 36$
 $x^{2} - 13x + 36 = 13x - 13x - 36 + 36$
 $x^{2} - 13x + 36 = 0$

 $x = \frac{-(-13) +/- \sqrt{(-13)^{2} - 4(1)(36)}}{2(1)}$


 $x = \frac{13 +/- \sqrt{169 - 144}}{2}$

 $x = \frac{13 +/- \sqrt{25}}{2}$

 $x = \frac{13 +/- 5}{2}$

 $x = 6.5 +/- 2.5$
 $x = 6.5 + 2.5$ $x = 6.5 - 2.5$
 $x = 9$ $x = 4$
----------------------------------------------------------------------------------------------------------
5. $3x^{2} - 7x + 2 = 0$

 $x = \frac{-(-7) +/- \sqrt{(-7)^{2} - 4(1)(2)}}{2(3)}$

 $x = \frac{7 +/- \sqrt{49 - 8}}{6}$

 $x = \frac{7 +/- \sqrt{41}}{6}$

 $x = \frac{7 +/- 6.403124237432849}{6}$

 $x = 1.167+/- 1.06718737290547$
 $x = 1.67 + 1.06718737290547$ $x = 1.167 - 1.06718737290547$
 $x = 2.73718737290547$ $x = 0.60281262709453$
----------------------------------------------------------------------------------------------------------
6. $10x^{2} - 10x + 9 = 5x^{2} + 4x + 1$
 $10x^{2} - 5x^{2} - 10x + 10x + 9 - 1 = 5x^{2} - 5x^{2} + 4x + 10x + 1 - 1$
 $5x^{2} + 8 = 14x$
 $5x^{2} - 14x + 8 = 14x - 14x$
 $5x^{2} - 14x + 8 = 0$

 $x = \frac{-(-14) + \sqrt{(-14)^{2} - 4(5)(8)}}{2(5)}$

 $x = \frac{14 +/- \sqrt{196 - 160}}{10}$

 $x = \frac{14 +/- \sqrt{36}}{10}$ .

 $x = \frac{14 +/- 6}{10}$

 $x = 1.4 +/- 0.6$
 $x = 1.4 + 0.6$ $x = 1.4 - 0.6$
 $x = 2$ $x = 0.8$

5 0

4 years ago

Easy points easy points

tatyana61 [14]

4 outta 16 or 4/16 I think

8 0

3 years ago

Read 2 more answers

Which of the following is an example of the associative property?

Mashutka [201]

Associative property is when you move the grouping symbols: ( and )
So the answer is B.

6 0