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2 years ago

By what least number should 648 be divided to get a perfect cube

Mathematics

1 answer:

mezya [45]2 years ago

6 0

Answer:

Step-by-step explanation:

a cube has six sides, so divide 648 by six

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URGENT PLEASE ANSWER QUICKLY!!!!!!!! (WILL MARK BRAINLYIST)

mina [271]

Answer:

for 10 people she makes 35$

for 20 people she makes 55$

for 30 people she makes 75$

and for 40 people she makes 95$

Step-by-step explanation:

just plug the number of people (10, 20, 30, 40) into the x in the equation.

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2 years ago

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aleksley [76]

Answer: ummm

Step-by-step explanation:

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2 years ago

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. Solve the equation. 2/3 x – 6 = 9

Allisa [31]

Hey there!

Okay let's get cracking :D

The equation is.... (2x/3) - 6 = 9

2x/3 = 15
2x = 45
x = 22.5 <----- And that is your answer!

I hope it helped!

Please vote for me as Brainliest if there is a second answer!

4 0

2 years ago

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Find n. 12/18 = n/36 n =

Semenov [28]

Answer:

n =24

Step-by-step explanation:

pretend n is x its just a normal fraction lol

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2 years ago

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Please help!! MathsWatch, Surd Expressions, Clip 207c

dexar [7]

Answer:

$A=(72+36\sqrt{3})\ mm^2$

Step-by-step explanation:

see the attached figure with letters to better understand the problem

Let

a ----> the height of rectangle in mm

b ---> the base of rectangle in mm

step 1

Find the base of rectangle

$b=AB+BC+CD+DE$ ----> by segment addition postulate

substitute

$b=3+3+3+3=12\ mm$

step 2

Find the height of rectangle

$a=FB+CG+GH$ ---> by segment addition postulate

substitute the given values

$a=3+CG+3\\a=6+CG$

Find the length sides CG

Applying the Pythagorean Theorem

$BG^2=BC^2+CG^2$

substitute the given values

$6^2=3^2+CG^2$

$CG^2=6^2-3^2$

$CG=\sqrt{27}\ mm$

simplify

$CG=3\sqrt{3}\ mm$

therefore

$a=(6+3\sqrt{3})\ mm$

step 3

Find the area of rectangle

$A=ab$

we have

$a=(6+3\sqrt{3})\ mm$

$b=12\ mm$

substitute

$A=(6+3\sqrt{3})(12)=(72+36\sqrt{3})\ mm^2$

8 0

3 years ago