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Dovator [93]
3 years ago
14

Which function has zeros at x = -2 and x = 5? ​

Mathematics
1 answer:
OlgaM077 [116]3 years ago
5 0

Answer:

f(x) = x² - 3x - 10

Step-by-step explanation:

Given zeros x = - 2 and x = 5, then the corresponding factors are

(x + 2) and (x - 5) , so

f(x) = (x + 2)(x - 5) ← expand using FOIL

     = X² - 3X - 10

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In short, Your Answer would be Option B

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PLEASE HELP "What is the value of x in the triangle" (15 Points)
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The answer is B.) 3

Step-by-step explanation:

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Sara threw 6 darts at this dartboard, and they all hit the target. Which of the following numbers could have been her score: 4,2
Vanyuwa [196]

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everything but 4 and 31!

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24: 9+9+1+1+1+3

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3 years ago
What is the product of (-6.8)^2
zlopas [31]

-6.8^2

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-6.8 squared = 46.24 (Notice that the answer is positive!)

8 0
3 years ago
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Find the tangent of the angle in between the lines 2x+3y–5=0 and 5x=7y+3?
tino4ka555 [31]

Answer:

-29/31

Step-by-step explanation:

We are given;

The equations;

2x+3y–5=0 and 5x=7y+3

We are required to determine the tangent of the angle between the two lines;

We need to know that;

When an equation is written in the form of, y = mx + c

Then, tan θ = m , where θ is the angle between the line and the x-axis.

Therefore, we can find the tangent of the angle between each line given and the x-axis.

2x+3y–5=0

we first write it in the form, y = mx + c

We get, y = -2/3x + 5/3

Thus, tan θ₁ = -2/3

5x=7y+3

In the form of y = mx + c

We get; y = 5/7x - 3/7

Thus, tan θ₂ = 5/7

Using the formula, θ = tan^-1((m1-m2)/(1+m1m2)) , where θ is angle between the two lines.

Thus, the tangent of the angle between the two lines will be;

tan θ = ((m1-m2)/(1+m1m2))

        = ((-2/3-5/7)/(1 + (-2/3 × 5/7)))

        = -29/21 ÷ 31/21

        = -29/31

Thus, the tangent of the angle between the two lines is -29/31

7 0
3 years ago
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