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marissa [1.9K]
2 years ago
12

A time line is a useful way to represent important dates and events throughout history. It's common to divide a historical time

line into events that occurred either BC (to the left of zero) or AD (to the right of zero). The year you're living in right now takes place in AD. BC AD 0 When performing mathematical operations involving dates, we can think of a historical time line as a number line. On the number line, the years increase from left to right. If zero represents the origin, the years to the right of zero are considered positive numbers and the years to the left of zero are considered negative numbers. Using this analogy, here are some events that might appear on a historical number line:
Event Historical Time Line Number Line

(The first ancient games take place in Olympia, Greece. 776 BC -776)

(Construction begins on the Great Wall of China. 221 )

(BC -221 World War I begins in central Europe. AD 1914 1,914 (or 1914)

Use these ideas about time lines and number lines to answer the questions that follow.
Part A The year in which the US Civil War ended was 25 percent later than the year Christopher Columbus set sail from Spain. If c represents the year Columbus set sail, we can write the year the Civil War ended as C +0.25c.
Rewrite this expression as a single term.​
Mathematics
1 answer:
fiasKO [112]2 years ago
7 0
The answer is... B

Hope this helps!!
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The length of a rectangle is 5 less than twice its width. Find the perimeter of this rectangle if its area is 273 yd2
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Let the width be w.

Therefore we know that the length 2w - 5.

We know that area is A = w*l.

Therefore:

273 = w * (2w-5)

Now we can solve for the width.

273 = 2w^2 - 5w

2W^2 - 5w - 273 = 0
We can use the quadratic formula from here where a = 2, b = -5 and c = 273.
w =  \frac{-b \pm  \sqrt{b^2 -4ac} }{2a}

w = \frac{-(-5) \pm \sqrt{-5^2 -4(2)(-273} }{2(2)}
Solving this gives us the possible answers of 13 and - \frac{21}{2}. Since our width can't be negative, we know the answer is 13.
Next, we can plug 13 into the formula for area to find the length.
273 = 13*l
21 = l
We now know the width and length. Finally, the last thing to do is calculate the perimeter using the formula 2w + l2 = P

2(13) + 2(21) = P
26 + 42 = P
68 = P
So, the perimeter of the rectangle is 68 yards.
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