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OleMash [197]
2 years ago
14

Giving brainliest easy question please help me :)))

Mathematics
1 answer:
ASHA 777 [7]2 years ago
6 0

Answer:

x=0.9

Step-by-step explanation:

(ask me if u want it)

You might be interested in
F(x) = 9 + 4x f(0) = f(-1) = Find the value of x for which f(x) =6 x=
puteri [66]

Answer: x=-3/4

Step-by-step explanation:

Since we know f(x)=6, we can set it equal to the equation.

6=9+4x           [subtract 9 on both sides]

-3=4x              [divide both sides by 4]

x=-3/4

8 0
3 years ago
Find the value of N<br> 6:7 = n : 4 : 2
Aleksandr-060686 [28]

Answer:

3.428 or 3 wholes 3/7

Step-by-step explanation:

6 : 7 = n : 4 : 2

6 : 7 = n : 4

6/7 = n/4

7n = 24

n = 24 /7

n = 3. 428 or 3 wholes 3/7

4 0
2 years ago
Determine the number of real solutions of -2x2 + 5x - 3 = 0.
andrew11 [14]

-2x^2 + 5x -3 =0

Find the discriminate:

In the given formula a = -2, b = 5 and c = -3

The discriminate is found using the formula b^2 - 4(ac)

Replace the letters with their values:

5^2 - 4(-2*-3)

25 - 4*6

25-24 = 1

When the discriminate is greater than or equal to 0, there are two real solutions.

The answer is c) 2

4 0
3 years ago
What is 9 1/2 x 1/4? i just need it for a math question on study island.
liberstina [14]

Answer:

2 \frac{3}{8}

Step-by-step explanation:

9 \frac{1}{2}  \times  \frac{1}{4}  \\  \frac{19}{2}  \times  \frac{1}{4}  \\  =  \frac{19}{8}  \\  = 2 \frac{3}{8}

hope this helps

brainliest appreciated

good luck! have a nice day!

4 0
3 years ago
Read 2 more answers
. Quantas senhas com 4 algarismos diferentes podemos escrever com os algarismos 1, 2, 3, 4, 5, 6?
ruslelena [56]

Answer:

We can write 360 distinct passwords using the numbers 1, 2, 3, 4, 5, and 6.

Step-by-step explanation:

We have to find how many passwords with 4 different digits can we write with the numbers 1, 2, 3, 4, 5, and 6.

Firstly, it must be known here that to calculate the above situation we have to use Permutation and not combination because here the order of the numbers in a password matter.

Since we are given six numbers (1, 2, 3, 4, 5, and 6) and have to make 4 different digits passwords.

  • Now, for first digit of the password, we have 6 possibilities (numbers from 1 to 6).
  • Similarly, for second digit of the password, we have 5 possibilities (because one number from 1 to 6 has been used above and it can't be repeated).
  • Similarly, for the third digit of the password, we have 4 possibilities (because two numbers from 1 to 6 have been used above and they can't be repeated).
  • Similarly, for the fourth digit of the password, we have 3 possibilities (because three numbers from 1 to 6 have been used above and they can't be repeated).

So, the number of passwords with 4 different digits we can write = 6 \times 5 \times 4 \times 3  = 360 possibilities.

Hence, we can write 360 distinct passwords using the numbers 1, 2, 3, 4, 5, and 6.

4 0
2 years ago
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