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3 years ago

The ratio of carbon-14 to carbon-12 in a piece of wood discovered in a cave is R = 1/917. Estimate the age of the piece of wood

Mathematics

1 answer:

Colt1911 [192]3 years ago

7 0

Answer:

The answer is " $\bold{6.6 \times 10^{12}\ years}$ "

Step-by-step explanation:

Let the given value is:

$R=\frac{1}{9^{17}}\\\\\to \frac{N_{c_{14}}}{N_{c_{12}}}=\frac{1}{9^{17}}\\\\\to t=\frac{2.303 \times 9^{17}}{5717}=6.6\times 10^{12}\ years$

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The answer is a space contains at least four points that do not lie in a same plane or not all in the same plane. An axiom is a statement or proposition that is observed as being established, accepted, or self-evidently true. In other words, it is any statement or mathematical statement that functions as a starting point from which other statements are logically derived. So this can be found on postulate 1 that states “a line containing at least two points; a plane contains at least three points not all in one line; and a space contains at least four points not all in the one plane.”

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ludmilkaskok [199]

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Determine the most precise name for ABCD (parallelogram, rhombus, rectangle, or square). Explain how you determined your answer.

Sonja [21]

<h3>Answer: Rhombus</h3>

======================================================

Reason:

Let's find the distance from A to B. This is equivalent to finding the length of segment AB. I'll use the distance formula.

$A = (x_1,y_1) = (3,5) \text{ and } B = (x_2, y_2) = (7,6)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(3-7)^2 + (5-6)^2}\\\\d = \sqrt{(-4)^2 + (-1)^2}\\\\d = \sqrt{16 + 1}\\\\d = \sqrt{17}\\\\d \approx 4.1231\\\\$

Segment AB is exactly $\sqrt{17}$ units long, which is approximately 4.1231 units.

If you were to repeat similar steps for the other sides (BC, CD and AD) you should find that all four sides are the same length. Because of this fact, we have a rhombus.

-------------------------

Let's see if this rhombus is a square or not. We'll need to see if the adjacent sides are perpendicular. For that we'll need the slope.

Let's find the slope of AB.

$A = (x_1,y_1) = (3,5) \text{ and } B = (x_2,y_2) = (7,6)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{6 - 5}{7 - 3}\\\\m = \frac{1}{4}\\\\$

Segment AB has a slope of 1/4.

Do the same for BC

$B = (x_1,y_1) = (7,6) \text{ and } C = (x_2,y_2) = (6,2)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{2 - 6}{6 - 7}\\\\m = \frac{-4}{-1}\\\\m = 4\\\\$

Unfortunately the two slopes of 1/4 and 4 are not negative reciprocals of one another. One slope has to be negative while the other is positive, if we wanted perpendicular lines. Also recall that perpendicular slopes must multiply to -1.

We don't have perpendicular lines, so the interior angles are not 90 degrees each.

Therefore, this figure is not a rectangle and by extension it's not a square either.

The best description for this figure is a <u>rhombus</u>.

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