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ikadub [295]
3 years ago
14

Help find missing side set up cosine ratio to solve???

Mathematics
2 answers:
Luda [366]3 years ago
7 0

Answer:

sjsosowueuwowueyeoowow

kramer3 years ago
6 0

Answer:

Step-by-step explanation:

Yes!

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All you need is below please help
Solnce55 [7]

Answer: d

Step-by-step explanation:

4 0
3 years ago
Help pls I don't understand
Oliga [24]

Answer:

me too a I don't understand

5 0
2 years ago
Y varies directly as X , and Y=1.2 when X=1.6.Solve for points.
Musya8 [376]

Answer:

No

Step-by-step explanation:

I don' think that Y varies directly like X does because first they're different numbers. Y=1.2 and X=1.6.

3 0
3 years ago
Read 2 more answers
The sum of two numbers is -50. Their difference is - 10. Find the numbers.
True [87]

Answer:

Larger is -30

Smaller is -20

Step-by-step explanation:

-50/2 = -25

difference is -10

add 5 to one number minus 5 from the other

so

-25 - 5 = -30

-25 + 5 = -20

Hope this helps :)

7 0
3 years ago
Read 2 more answers
According to a study conducted in one​ city, 25​% of adults in the city have credit card debts of more than​ $2000. A simple ran
Anvisha [2.4K]

Answer:

The sampling distribution of \hat p is <em>N</em> (0.25, 0.0354²).

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes <em>n</em> > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

 \mu_{\hat p}=p

The standard deviation of this sampling distribution of sample proportion is:

 \sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}

Let <em>p</em> = proportion of adults in the city having credit card debts of more than​ $2000.

It is provided that the proportion of adults in the city having credit card debts of more than​ $2000 is, <em>p</em> = 0.25.

A random sample of size <em>n</em> = 150 is selected from the city.

Since <em>n</em> = 150 > 30 the Central limit theorem can be used to approximate the distribution of <em>p</em> by the Normal distribution.

The mean is:

\mu_{\hat p}=p=0.25

The standard deviation is:

\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.25(1-0.25)}{150}}=0.0354

Thus, the sampling distribution of \hat p is <em>N</em> (0.25, 0.0354²).

3 0
3 years ago
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