HELP ASAP! Brainliest and 15 points! This is really important

Mathematics

1 answer:

Ivan3 years ago

3 0

Answer:

Step-by-step explanation:

The first one is the third root of 5^2. The denominator represents the root in which you're taking, in this case the third root, and the numerator represents the exponent that will be underneath the radical with the integer

The second one is the square root of 5. Anytime you see a 2 as the denominator in an exponent you're just taking the square root

The third one is the fifth root of 3^2, as explained by the first one

The fourth one is the square root of 3^5, as explained with the second one

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1 Calculator What is the area of this figure? Enter your answer in the box. units²

photoshop1234 [79]

Answer:

44 units²

Step-by-step explanation:

For triangles: (bases and heights of both triangles are equal)

Base = 4 units, height = 3 units

For trapezoid:

Base 1 = 5 units, base 2 = 3 units, height = 8 units

Area of figure = Area of two triangles + Area of trapezoid

= 2 *1/2 * base * height + 1/2(base 1+ base 2) *height

=4*3 + 1/2(5+3)*8

= 12 + 8*4

= 12 + 32

= 44 units²

7 0

3 years ago

A storage tank will have a circular base of radius r and a height of r. The tank can be either cylindrical or hemispherical (ha

Neko [114]

Answer:

Volume: $\frac{2}{3}\pi r^3$

Ratio: $\frac{2}{9}r$

Step-by-step explanation:

First of all, we need to find the volume of the hemispherical tank.

The volume of a sphere is given by:

$V=\frac{4}{3}\pi r^3$

where

r is the radius of the sphere

V is the volume

Here, we have a hemispherical tank: a hemisphere is exactly a sphere cut in a half, so its volume is half that of the sphere:

$V'=\frac{V}{2}=\frac{\frac{4}{3}\pi r^3}{2}=\frac{2}{3}\pi r^3$

Now we want to find the ratio between the volume of the hemisphere and its surface area.

The surface area of a sphere is

$A=4 \pi r^2$

For a hemisphere, the area of the curved part of the surface is therefore half of this value, so $2\pi r^2$ . Moreover, we have to add the surface of the base, which is $\pi r^2$ . So the total surface area of the hemispherical tank is