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3 years ago

Find the missing length indicated Please help, no links

Mathematics

2 answers:

siniylev [52]3 years ago

8 0

Answer:

x = 135

Step-by-step explanation:

m = length of perpendicular line to hypotenuse

81/m = m/144

m² = 81 x 144 = 11664

m =√11664 = 108

Using the Pythagorean theorem:

x² = 81² + 108² = 6561 + 11664 = 18225

x = √18225 = 135

luda_lava [24]3 years ago

7 0

9514 1404 393

Answer:

x = 135

Step-by-step explanation:

Side x is the geometric mean of the hypotenuse segments it touches.

x = √(81×(81+144)) = √81×√225 = 9×15

x = 135

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Given: KPST is a trapezoid, KP=ST, MN is a midsegment, MN=20, h=15, PS:KT=3:7 Find: KS and KP

lions [1.4K]

Answer:

Length of KS = 25 units and

Length of KP = 17 units.

Step-by-step explanation:

Given: KPST is a trapezoid, KP =ST, MN is a mid segment, h is the height =15

Also it is given that, MN = 20 , h = 15 and PS:KT = 3:7.

If two sides of the trapezoid are equal then, it is an isosceles trapezoid.

Mid-segment of a trapezoid is a line segment which connects the midpoints of the non-parallel sides.

A trapezoid mid segment connects the midpoints of two congruent sides of the trapezoid and is parallel to the pair of parallel sides.

Length of the mid segment is the sum of two bases divide by 2

Since, the length of Mid-segment MN = 20.

Also, it is given: PS:KT = 3:7

Let PS = 3x and KT = 7x respectively.

then;

$\frac{PS+KT}{2} = 20$

$\frac{3x+7x}{2} = 20$

$\frac{10x}{2} =20$

On Simplify, we get;

5x =20

Divide both sides by 5 we get;

x =4

Then:

Length of base PS = 3x = 3(4) = 12 and Length of base KT = 7x = 7(4) = 28.

Now, In triangle PLK

Using Pythagoras theorem to find KP;

It is given here, PL =h =15 and KL= 8 {you can see in the figure as shown below};

$KP^2= PL^2 + KL^2$

$KP^2 = 15^2+8^2 =225 +64 = 289$

$KP = \sqrt{289}$

Simplify:

KP = 17

therefore, the length KP = 17 units

To, construct a line: Join K and S

Now, in triangle KRS

KR = KL +LR = 8 +12 =20 and SR = h= 15

Using Pythagoras theorem in KRS to find KS;

$KS^2 = SR^2+KR^2$

$KS^2 = 15^2 + 20^2 = 225 + 400 = 625$

$KS = \sqrt{625}$

On simplify:

KS = 25

Therefore, the length of KS is, 25 units.

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20 POINTS!!! PLZ ANSWER!! On the moon, the time, in seconds, it takes for an object to fall a distance, d, in feet, is given by

scoundrel [369]

Answer:

Part a) $f(2)=1.57\ sec$

It takes 1.57 seconds for an object to fall a distance of 2 feet

Part b) see the explanation

Part c) $2,165.43\ sec$

Step-by-step explanation:

Let

f(d) -----> the time in seconds it takes for an object to fall

d -----> distance in feet

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$f(d)=1.11\sqrt{d}$

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we know that

f(2) represent the time in seconds it takes for an object to fall a distance of 2 feet

For $d=2\ ft$

substitute in the function above and solve for f(2)

$f(2)=1.11\sqrt{2}$

$f(2)=1.57\ sec$

therefore

It takes 1.57 seconds for an object to fall a distance of 2 feet

Part b) The imbrium basin is the largest basin on the moon. A reasonable domain for the height above the lowest point in the basin is given by {d|0 ≤ d ≤ 3805774}

What does this tell you about the basin?

The height of the basin is greater than or equal to 0 ft and less than or equal to 3,805,774 ft

The maximum height of the basin is 3,805,774 ft

Part c) How long would it take a rock to drop from the rim to the bottom of the basin?

we know that

The distance from the rim to the bottom of the basin is equal to the maximum height of the basin

$d=3,805,774\ ft$

substitute the value of d in the function f(d)

$f(d)=1.11\sqrt{3,805,774}$

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3 years ago