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Ad libitum [116K]
2 years ago
11

1

Mathematics
1 answer:
Liula [17]2 years ago
4 0

The addition of the functions f(x) and g(x) will be ln (2x) + 3 sin(x) – 22. Then the correct option is C.

<h3>What is a function?</h3>

A function is a statement, rule, or law that establishes the connection between two variables. In mathematics, functions are everywhere and are necessary for constructing physical connections.

The functions are given below.

f(x) = ln (2x) – 15

g(x) = 3 sin(x) – 7

Then the addition of the function will be

(f + g)(x) = f(x) + g(x)

(f + g)(x) = ln (2x) – 15 + 3 sin(x) – 7

(f + g)(x) = ln (2x) + 3 sin(x) – 22

Then the correct option is C.

More about the function link is given below.

brainly.com/question/5245372

#SPJ1

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Andreyy89

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90 hours

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The rate at which water enters the pool is

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3 years ago
The intensity of a sound varies inversely where of its distance from the source at a distance of 1 meter the intensity of a jet
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3 years ago
A student is given that point P(a, b) lies on the terminal ray of angle Theta, which is between StartFraction 3 pi Over 2 EndFra
Harman [31]

Answer:

<em>A.</em>

<em>The student made an error in step 3 because a is positive in Quadrant IV; therefore, </em>

<em />cos\theta = \frac{a\sqrt{a^2 + b^2}}{a^2 + b^2}

Step-by-step explanation:

Given

P\ (a,b)

r = \± \sqrt{(a)^2 + (b)^2}

cos\theta = \frac{-a}{\sqrt{a^2 + b^2}} = -\frac{\sqrt{a^2 + b^2}}{a^2 + b^2}

Required

Where and which error did the student make

Given that the angle is in the 4th quadrant;

The value of r is positive, a is positive but b is negative;

Hence;

r = \sqrt{(a)^2 + (b)^2}

Since a belongs to the x axis and b belongs to the y axis;

cos\theta is calculated as thus

cos\theta = \frac{a}{r}

Substitute r = \sqrt{(a)^2 + (b)^2}

cos\theta = \frac{a}{\sqrt{(a)^2 + (b)^2}}

cos\theta = \frac{a}{\sqrt{a^2 + b^2}}

Rationalize the denominator

cos\theta = \frac{a}{\sqrt{a^2 + b^2}} * \frac{\sqrt{a^2 + b^2}}{\sqrt{a^2 + b^2}}

cos\theta = \frac{a\sqrt{a^2 + b^2}}{a^2 + b^2}

So, from the list of given options;

<em>The student's mistake is that a is positive in quadrant iv and his error is in step 3</em>

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