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Lubov Fominskaja [6]
3 years ago
12

Helpppppppppppppppppppp

Computers and Technology
1 answer:
irga5000 [103]3 years ago
7 0
THE ANSWER IS B MOST DEFINITELY
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Vsevolod [243]

Improving SEO, by ensuring the URL matches the title of your

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<h3>What is SEO?</h3>

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During which phase of system development would you acquire any necessary hardware and software?
solmaris [256]

During the <u>design</u> phase of system development, you would acquire all the necessary hardware and software.

<h3>What is SDLC?</h3>

SDLC is an abbreviation for system development life cycle and it can be defined as a strategic methodology that defines the key steps, phases, or stages for the design, development and implementation of high quality systems.

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Also, phased implementation simply refers to an implementation methodology in which smaller portions of functionality of a system are typically implemented one at a time (one after the other).

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3 0
2 years ago
Programming challenge description: Given a string comprising just of the characters (,),{,},[,] determine if it is well-formed o
nadezda [96]

Answer:

Employing Java language,

Explanation:

//for using stack data structure

import java.util.Stack;

//class definition

public class BracketMatch {

   //function to find the string is well formed or not

   public static boolean isWellFormed(String str) {

       //variable to store the character value

       char ch;

       //check if the first character itself is the end of the brackets

       if (str.charAt(0) == ')'||str.charAt(0) =='}'||str.charAt(0) ==']')

           return false;

       //creating a stack of character type

       Stack<Character> stack = new Stack<Character>();

       //iterating through the characters in string

       for(int i=0; i < str.length(); i++) {

           //storing the current character from the string in the variable

           ch = str.charAt(i);

           if(ch == '('||ch=='{'||ch=='[')

               //if the character is starting of the brackets push it into stack

               stack.push(ch);

           else if(ch == ')')

               //if it is closing bracket and the stack is empty then the string is not well formatted

               if(stack.empty())

                   return false;

               else if(stack.peek() == '(')

                   stack.pop();

               else

                   return false;

           else if(ch == '}')

               if(stack.empty())

                   return false;

               else if(stack.peek() == '{')

                   stack.pop();

               else

                   return false;

       }

       //returning the stack content, if the string will be well formed the stack would be empty

       //after all the operations

       return stack.empty();

   }

   //main method

   public static void main(String[] args) {

       //calling function to find if the string is welll formatted or not

       System.out.println(isWellFormed("{}"));

       //calling function to find if the string is welll formatted or not

       System.out.println(isWellFormed("([)]"));

   }

}

5 0
4 years ago
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