Question

How do i solve this? - Linear Functions

Answer 1

Answer:

solve for y

Step-by-step explanation:

$5x-2y=-10$

subtract 5x from both sides

$5x-5x-2y=-10-5x$

$-2y=-10-5x$

Divide each term in the equation by -2

$\frac{-2y}{-2}=\frac{-10}{-2} -\frac{-5x}{-2}\\\\y=\frac{-10}{-2} +\frac{-5x}{-2} \\\\y=5+\frac{5x}{2}$

(negative+negative=positive)

re-write in slope-intercept form $y=mx+b$ , where m is the slope and b is the y-intercept

$y=\frac{5}{2}x+5$

Now you know that the slope is $\frac{5}{2}x$ and the y-intercept is $5$.

Now, to graph, you just need to choose random values for x (like 0,1,2,3 or any other number) and insert into the equation $y=\frac{5}{2}x+5$ to find the points, or you can just use the slope. To find the x-intercept, do the following:

make y equal to 0

$0=\frac{5}{2}x+5$

Solve for x:

simplify $\frac{5}{2}x$

$0=\frac{5x}{2} +5$

Subtract 5 from both sides

$0-5=\frac{5x}{2}+5-5\\ \\-5=\frac{5x}{2}$

Multiply both sides by 2

$2(-5)=2(\frac{5x}{2})\\\\-10=5x$

Divide both sides by 5

$\frac{-10}{5}= \frac{5x}{5}\\\\-2=x$

Flip

$x=-2$

The x-intercept is -2.