Answer:
The probability that a call last between 4.2 and 4.9 minutes is 0.4599
Step-by-step explanation:
Let X be the length in minutes of a random phone call. X is a normal distribution with mean λ=4.2 and standard deviation σ=0.4. We want to know P(4.2 < X < 4.9). In order to make computations, we will use W, the standarization of X, given by the following formula

We will use
, the cummulative distribution function of W. The values of
are well known and the can be found in the attached file

We conclude that the probability that a call last between 4.2 and 4.9 minutes is 0.4599
Answer:
Hi there
The formula is
A=p (1+r)^t
A future value
P present value
R interest rate
T time
A) A=2,000×(1+0.04)^(3)=2,249.728
B) A=2,000×(1+0.04)^(18)=4,051.63
C) 2500=2000 (1+0.04)^t
Solve for t
T=log(2,500÷2,000)÷log(1+0.04)
T=5.7 years
D) t=log(3,000÷2,000)÷log(1+0.04)
t=10.3 years
Hope it helps
Step-by-step explanation:
I think it is 0.4/0.4 but I'm not sure