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drek231 [11]
3 years ago
15

For the function f(x)=1/x which of these could be a value of F(x) when x is close to zero

Mathematics
2 answers:
alukav5142 [94]3 years ago
7 0

Answer:

The function in quadrant I, where y is increasing upward.

Step-by-step explanation:

The smaller x becomes, the larger f(x) becomes. The answer is that f(x) or y approaches infinity as x becomes smaller and smaller. This helps to understand why division by zero is undefined.

Here you go! Hope this helps!! :-)

Sindrei [870]3 years ago
4 0

Answer:

-10,000

Step-by-step explanation:

apex ;)

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344531 to the nearest tenth
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What is the geometric mean of 3 and 147?
pychu [463]

to find the geometric mean, multiply them together, then take the square root

3*147

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Read 2 more answers
A 2000 gallon fish aquarium can be filled by water flowing at a constant rate in 10 hours. When a decorativve rock is placed in
Elza [17]

Answer:

The volume of the rock is 13.368 cubic feet.

Step-by-step explanation:

The volume of the rock (V_{r}), measured in gallons, is equal to the volume of the fish aquarium without the decorative rock (V') minus the volume of the fish aquarium with the decorative rock (V''), both measured in gallons.

Since the water flow is at constant rate, the volume of the rock is expressed by the following equation:

V_{r} = V' - V''

V_{r} = \dot V \cdot (\Delta t_{1}-\Delta t_{2}) (1)

Where:

\dot V - Flow rate, measured in gallons per hour.

\Delta t_{1} - Filling time of the fish aquarium without the decorative rock, measured in hours.

\Delta t_{2} - Filling time of the fish aquarium with the decorative rock, measured in hours.

And the flow rate is:

\dot V = \frac{2000\,gal}{10\,h}

\dot V = 200\,\frac{gal}{h}

The flow rate is 200 gallons per hour.

If we know that \dot V = 200\,\frac{gal}{h}, \Delta t_{1} = 10\,h and \Delta t_{2} = 9.5\,h, then the volume of the rock is:

V_{r} = \left(200\,\frac{gal}{h}\right)\cdot (10\,h-9.5\,h)

V_{r} = 100\,gal

V_{r} = 13.368\,ft^{3}

The volume of the rock is 13.368 cubic feet.

8 0
3 years ago
1. Calculate the density of gold using the information given.
schepotkina [342]

Answer:

Step-by-step explanation:

Mass m=25 g

Volume V=1.29 cm³

density D=M/V

=25/1.29

≈19.38

≈19 g/cm³

4 0
3 years ago
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