All categories

2 years ago

What is equivalent to 15+3x

Mathematics

1 answer:

Mekhanik [1.2K]2 years ago

7 0

Answer:

maybe 3(5+x)

Step-by-step explanation:

I don't know if this is what you're looking for but if you factor the expression that is what you would get. It is something equivalent.

You might be interested in

How do I solve numbers 8 and 9?

Tresset [83]

8: 20
9: 90
I am so sorry if this is wrong. I am not good at this type of things

7 0

2 years ago

Parallel lines j and k are cut by transvesal t . Which statement is true about ∠2 and ∠6

almond37 [142]

Answer:

They both equal

Step-by-step explanation:

5 0

3 years ago

Please, PLEASE answer this fast! I have 1 hour left before I pass it. Please help :( answer it properly! Thank you in advance.

Inessa05 [86]

Answer:

The range is is set of all second pairs (y-coordinates) while the domain is the set of first pairs(x-coordinates)

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Haley makes earrings and packages them into cube boxes that measure 1/6 foot wide. how many 1/6 foot cubic boxes can she fit int

navik [9.2K]

Answer: $28\ cubes$

Step-by-step explanation:

The volume of a cube can be found with this formula:

$V_{(c)}=s^3$

Where "s" is the lenght of any edge of the cube.

The formula for calculate the volume of a rectangular prism is:

$V_{rp}=lwh$

Where "l" is the lenght, "w" is the width and "h" is the height.

We need to find the volume of a cube box:

$V_1=s^3=(\frac{1}{6}ft)^3=\frac{1}{216}ft^3$

To find the volume of the shipping box, first we must convert the mixed number to an improper fraction:

$1\frac{1}{6}=\frac{(6*1)+1}{6}=\frac{7}{6}$

Then the volume of the shipping box is:

$V_2=lwh\\\\V_2=(\frac{7}{6}ft)(\frac{1}{3}ft)(\frac{1}{3}ft)=\frac{7}{54}ft^3$

Now, in order to find the number of cube boxes can Haley fits into a shipping box, you must divide the the volume of the shipping box by the volume of one cube. This is:

$\frac{\frac{7}{54}ft^3}{\frac{1}{216}ft^3}=28$

6 0

3 years ago

What are the critical values for a two-tailed test with a 0.01 level of significance when n is large and the population standard

Sunny_sXe [5.5K]

For a two-tailed test we need to halve 0.01, giving 0.005. Then we need to sutract 0.005 from 0.5, giving 0.5 - 0.005 = 0.495. Looking up the p value of 0.495 in an inverse normal probability table we obtain the value z = 2.5758. Therefore the critical values are -2.5758 and 2.5758.

4 0

3 years ago