Answer:
0.5 = 50% probability a value selected at random from this distribution is greater than 23
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the probability a value selected at random from this distribution is greater than 23?
This is 1 subtracted by the pvalue of Z when X = 23. So



has a pvalue of 0.5
0.5 = 50% probability a value selected at random from this distribution is greater than 23
You can just multiply the top and the bottom by 2, to get the bottom to be 10. So you get -164/10. From here you can see that 10 goes into 164,16.4 times.
Therefore, -82/5 = -16.4
Answer:
Length = 17 feet, Width = 5 feet
Step-by-step explanation:
Given:
The area of a rectangular wall of a barn is 85 square feet.
Its length is 12 feet longer than the width.
Question asked:
Find the length and width of the wall of the barn.
Solution:
Let width of a rectangular wall of a barn = 
<u>As length is 12 feet longer than the width.</u>
Length of a rectangular wall of a barn = 
As we know:


Subtracting both sides by 85

As width can never be in negative, hence width of a rectangular wall of a barn =
= 5 feet
Length of a rectangular wall of a barn = 
Therefore, length and width of the wall of the barn is 17 feet and 5 feet respectively.
The zeros of the given functions are shown on the attached picture.
Answer:
the answer is d. 4x²+x-6
Step-by-step explanation:
In order to combine the fractions, they need to have the same denominator.
So, multiply each of their numerators by the denominator they need to be equivalent.
This would look like this:
3x/x+3 --> 3x(x)/x(x+3) ---simplify this as--> 3x²/x(x+3)
x-2/x --> (x-2)(x+3)/x(x+3) ---simplify this as --> x²+x - 6/x(x+3)
3x 3x(x) x-2 (x-2)(x+3)
----- ---> ----- and -------- ---> ---------
x+3 x(x+3) x x(x+3)
now that both fractions have the same denominator, we can add their numerators.
3x² + x²+x-6 = 4x²+x -6
This should now look like this:
4x²+x -6
-------------
x(x+3)