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Svetllana [295]
3 years ago
15

Seema covered 3 4/13(three four by thirteen)km by bus,2 5/13(Two five by thirteen)km by metro and 1 2/13(One two by thirteen)km

by a rickshaw.What is the total distance covered by Seema?
Mathematics
1 answer:
Ad libitum [116K]3 years ago
6 0

Answer: 89/13 km

Step-by-step explanation:

3 4/13 + 2 5/13 + 1 2/13

= 43/13 + 31/13 + 15/13

= 89/13 km

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Answer:

<em><u>5</u></em><em><u> </u></em><em><u>points</u></em><em><u> </u></em><em><u>question</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>8</u></em>

<em><u>and</u></em><em><u> </u></em><em><u>2</u></em><em><u> </u></em><em><u>po</u></em><em><u>ints</u></em><em><u> questions</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>3</u></em><em><u>0</u></em><em><u> </u></em><em><u>!</u></em><em><u>!</u></em>

Step-by-step explanation:

Let the number of 5 points questions be x and number of the 2 points questions be y !!

Given :- The paper has 38 problems

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number of 5 points Q + number of 2point Q = 38

=> x + y = 38

=> x = 38 - y .... ( i )

And , The test worth 100 pts :-

There must be x number of Questions which carry 5 points and there must y number of questions which carries 2 points ( as assume above )

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Putting value of the x in ( ii )

5 ( 38 - y ) + 2y = 100

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