Answer:
Answer: LCM of 3 and 15 is 15. 2.
Step-by-step explanation:
Hope this helps
Answer:
D. {x:-8≤x<-5}
Step-by-step explanation:
x≥-8
x={-8,-7,-6,-5,-4,-3,-2,-1,0...}
x<-5
x={-6,-7,-8,-9,-0...}
Numbers equal to or less than -8 are also less than -5
Hope it helps ;) ❤❤❤
Answer:
I just need points
Step-by-step explanation:
I just need points
We need to determine the radius and diameter of the circle. If the area of the circle is 10 pi in^2, then, according to the formula for the area of a circle,
A = 10 pi in^2 = pi*r^2. Thus, 10 in^2 = r^2, and r = radius of circle = sqrt(10) in.
Thus, the diam. of the circle is 2sqrt(10) in. This diam. has the same length as does the hypotenuse of one of the triangles making up the square.
Thus, [ 2*sqrt(10) ]^2 = x^2 + x^2, where x represents the length of one side of the square. So, 4(10) in^2 = 2x^2. Then:
40 in^2 = 2x^2, or 20 in^2 = x^2, and so the length x of one side of the square is sqrt(20). The area of the square is the square of this result:
Area of the square = x^2 = [ sqrt(20) ]^2 = 20 in^2 (answer). Compare that to the 10 pi sq in area of the circle (31.42 in^2).