You made a mistake with the probability
, which should be
in the last expression, so to be clear I will state the expression again.
So we want to solve the following:
Conditioned on this event, show that the probability that her paper is in drawer
, is given by:
(1)
and
(2) 
so we can say:
is the event that you search drawer
and find nothing,
is the event that you search drawer
and find the paper,
is the event that the paper is in drawer 
this gives us:


Solution to Part (1):
if
, then
,
this means that

as needed so part one is solved.
Solution to Part(2):
so we have now that if
=
, we get that:

remember that:

this implies that:

so we just need to combine the above relations to get:

as needed so part two is solved.
(3)^-4 = 0.01234567901
(-3/7)^-2 = <span>5.44444444444</span>
The answer to your question
is 12
Answer:
Ted is 6 years old
Leon is 7 years old
Andrew is 8 years old
Step-by-step explanation:
Ted+Leon=13 ⇒T+L=13 ⇒L=13-T
Leon+Andrew=15 ⇒L+A=15 ⇒A=15-L ⇒A=15-(13-T) because Leon =13-Ted
A=2+T
Ted+Andrew=14
T+A=14 ( substitute Andrew age from A=2+T)
T+2+T=14
2T=12
<h2>T=12/2=6 (Ted is 6 years old)</h2><h2>A=2+T=2+6=8 ( Andrew is 8 years old)</h2><h2>Leon=13-T=13-6=7 ( Leons is seven years old)</h2>
check: Ted+Leon=13 ⇒ 6+7=13
Leon + Andrew=15 ⇒7+8=15
Andrew+Ted=14 ⇒ 6+8=14
Answer:
where's the worksheet
Step-by-step explanation: