SA = 2 pi r^2 + 2 pi r h
SA = 2 * pi * 25 + 2 pi * 5 * 13
SA = 565.2 in ^3
this is using 3.14 for pi
Complete Question
Suppose there was a cancer diagnostic test was 95% accurate both on those that do and 90% on those do not have the disease. If 0.4% of the population have cancer, compute the probability that a particular individual has cancer, given that the test indicates he or she has cancer.
Answer:
The probability is 
Step-by-step explanation:
From the question we are told that
The probability that the test was accurate given that the person has cancer is

The probability that the test was accurate given that the person do not have cancer is

The probability that a person has cancer is

Generally the probability that a person do not have cancer is

=> 
=> 
Generally the probability that a particular individual has cancer, given that the test indicates he or she has cancer is according to Bayes's theorem evaluated as

=> 
=> 
Answer:
I believe the answer is 45
Step-by-step explanation:
First do the parentheses: 12-2=10
Then do the exponent: 3^2=3*3=9
Next multiply 9 by 10: 9*10=90
Lastly divide 90 by 2: 90/2=45
Answer:
can you show a pic tell me in the comments
Step-by-step explanation:
If you would like to solve the equation k / 2 + 9 = 30, you can calculate this using the following steps:
k / 2 + 9 = 30
k / 2 = 30 - 9
k / 2 = 21 /*2
k = 21 * 2
k = 42
The result is 42.