B. Ice-albedo feedback
Explanation:
The ice-albedo feedback is one process that can significantly increase the rate of greenhouse emissions in response to a decreased albedo.
Albedo is the ratio of reflected light to incident light.
A decrease in albedo suggests that a surface is absorbing more light than it is reflecting. This is typical of areas with land cover and vegetation.
Areas with a high reflectivity have a high albedo. Snow, ice and polar regions are good reflectors of solar radiation. They have a very high albedo close to 100%. Much of the surface area is buried with ice.
Examples of greenhouse gases are carbon dioxide, methane, water vapor e.t.c
How does a low albedo relates to increase in greenhouse gas emission?
- The ice-albedo feedback can substantially contribute to greenhouse gas emission.
- The high reflectivity of ice causes long wave radiation to warm the air around a icy body in polar regions.
- When ice melts, they leave land bare and exposed.
- Melt water collects in pockets.
- Exposed land leads to a decrease in albedo.
- Organisms can thrive more in warm terrain.
- Also, pockets of carbon dioxide gases trapped in ice is released.
- Organisms release carbon dioxide into the atmosphere during cellular respiration.
- Soils originally permafrost will become stable and this will encourage more human occupation of the area.
- All these activities leads to an increase in the emission of greenhouse gases in an area with low albedo.
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Greenhouse emission brainly.com/question/4580761
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Answer:The might likely die.
Explanation:
Phloem and xylem tissues are the major conducting tissues in plant. Xylem conduct ( transports) water and minerals salts from the soil through the roots to all parts of the plant while phloem conducts manufactured food from the leaves to other parts of the plant.
Now, if the phloem of a seed plant is damaged and not functioning well, the manufactured food will not get to other parts of the plant where it is needed or supposed to be stored.
If the plant is no longer getting these nutrients, its growth and development will be affected. It might lead to the death of the plant.
Answer:
50%
Explanation:
Let's assume that the allele "T" gives the normal phenotype while the recessive allele "t" imparts the disease and is lethal in homozygous condition. The genotype of each of the two carrier parents would be "Tt". A cross between Tt and Tt would give the progeny in the following genotype ratio=
Tt x Tt= 1/4 TT: 1/2 Tt: 1/4 tt
Therefore, 1/2 or 50% progeny would be the carrier for the Tay-Sachs disease.
Binary fission is a characteristic of prokaryotes and a few eukaryote species and is most similar to the process of mitosis; each parent cell divides into two daughter cells each containing half of the genetic material from the parent cell.
