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Leya [2.2K]
3 years ago
10

Besty has $27 saved. This month she saved an additional $9. She wants to buy packs of colored string to make bracelets. Each pac

k costs $6. Besty says she now has enough money to buy 6 packs. Carl says she has enough money to buy only 3 pack. I Besty or Carl correct? Explain your answer
Mathematics
2 answers:
aalyn [17]3 years ago
7 0

Answer:

Yes, Besty is correct.

Step-by-step explanation:

$27 + $9 = 36. 36 divided by 6 is 6. Besty would only be able to buy 3 packs if each pack costed $12 (36 divided by 12 is 3).

Vedmedyk [2.9K]3 years ago
5 0
Besty is correct. Believe me
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Which of the following is equal to the fraction below?
Talja [164]

Answer:

C

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4 0
2 years ago
1) Members at a yoga school pay $10 per class plus a one-time $100 membership fee. Non-members pay$15 per class. How many classe
Juli2301 [7.4K]

Answer:

Part 1) The number of classes must be greater than 20

Part 2) see the explanation

Part 3) \$68.76

Part 4) \$12\ per\ hour

Part 5) The equation that can be used is 27x=242.73  and the cost of one print is \$8.99

Part 6) The number of classes must be greater than 30

Step-by-step explanation:

Part 1) we know that

The linear equation in slope intercept form is equal to

y=mx+b

where

m is the slope or unit rate

b is the y-intercept or initial value

Let

y ----> the total cost

x ----> the number of classes

we have

<em>Members</em>

The slope is m=\$10\ per\ class

The y-intercept is b=\$100

so

y=10x+100 ----> equation A

<em>Non-Members</em>

The slope is m=\$15\ per\ class

so

y=15x ----> equation B

To find out how many classes would a member have to take to save money compared to taking classes as a non-member, solve the following inequality

10x+100 < 15x

Solve for x

subtract 10 x both sides

100 < 15x-10x

100 < 5x

Divide by 5 both sides

20 < x

Rewrite

x > 20

therefore

The number of classes must be greater than 20

Part 2) we have

The sum of 8 and 3 times a number is 23.

Let

x ----> the number

Remember that

3 times a number is the same that multiply 3 by the number ----> 3x

so

The sum of 8 and 3 times a number is 23 is the same that

8+3x=23

solve for x

subtract 8 both sides

3x=23-8

3x=15

Divide by 3 both sides

x=5

Part 3) we know that

The linear equation in slope intercept form is equal to

y=mx+b

where

m is the slope or unit rate

b is the y-intercept or initial value

Let

y ----> the total cost of renting a car for one day

x ----> the number of miles

we have

The slope is m=\$0.42\ per\ mile

The y-intercept is b=\$36

so

y=0.42x+36

For x=78 miles

substitute in the linear equation and solve for y

y=0.42(78)+36

y=\$68.76

Part 4) Let

x ----> Alice's normal hourly rate

we know that

40 hours multiplied by her normal hourly rate plus 10 hours (50 h-40 h) multiplied by 1.5 times her normal hourly rate must be equal to $660

so

The linear equation that represent this situation is

40x+10(1.5x)=660

solve for x

40x+15x=660

55x=660

Divide by 55 both sides

x=\$12\ per\ hour

Part 5) Let

x ----> the cost of one print

we know that

The cost of one print multiplied by 27 prints must be equal to $242.73

so

The linear equation is equal to

27x=242.73

solve for x

Divide by 27 both sides

x=\$8.99

Part 6) we know that

The linear equation in slope intercept form is equal to

y=mx+b

where

m is the slope or unit rate

b is the y-intercept or initial value

Let

y ----> the total cost

x ----> the number of classes

we have

<em>Members</em>

The slope is m=\$7\ per\ class

The y-intercept is b=\$120

so

y=7x+120 ----> equation A

<em>Non-Members</em>

The slope is m=\$11\ per\ class

so

y=11x ----> equation B

To find out how many classes would a member have to take to save money compared to taking classes as a non-member, solve the following inequality

7x+120 < 11x

Solve for x

subtract 7x both sides

120 < 11x-7x

120 < 4x

Divide by 4 both sides

30 < x

Rewrite

x > 30

therefore

The number of classes must be greater than 30

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