Answer:
Below in bold.
Step-by-step explanation:
Total number of marbles = 3+4+5 = 12
P(white, red) = 4/12 * 3/11
= 12/132
= 1/11,
P(blue, white, red) = 5/12 * 4/11* 3/10
= 60/1320
= 6/132
= 1/22.
Answer:
water reflects 5.6 times as many uv rays as sand
------------------------
Step-by-step explanation:
sand: 0.15
water: 21/25 --> 0.84
0.84/0.15= 5.6
therefore, water reflects 5.6 times as many uv rays as sand
Answer:
D is closest
Step-by-step explanation: Snap add?
1. f(x)*g(x)
![\sqrt{x^{2}+12x+36}*x^{3}-12](https://tex.z-dn.net/?f=%5Csqrt%7Bx%5E%7B2%7D%2B12x%2B36%7D%2Ax%5E%7B3%7D-12)
![(x^{2}+2\sqrt{3}x+6)*(x^{3}-12)](https://tex.z-dn.net/?f=%28x%5E%7B2%7D%2B2%5Csqrt%7B3%7Dx%2B6%29%2A%28x%5E%7B3%7D-12%29)
![(x^{3}-12)(x^{2}+2\sqrt{3}x+6)](https://tex.z-dn.net/?f=%28x%5E%7B3%7D-12%29%28x%5E%7B2%7D%2B2%5Csqrt%7B3%7Dx%2B6%29)
![(x^{3}-12)(x^{2}+2\sqrt{3}x+6)\\\\x^5+2\sqrt{3}x^4+6x^3-12x^2-24\sqrt{3}x-72\\](https://tex.z-dn.net/?f=%28x%5E%7B3%7D-12%29%28x%5E%7B2%7D%2B2%5Csqrt%7B3%7Dx%2B6%29%5C%5C%5C%5Cx%5E5%2B2%5Csqrt%7B3%7Dx%5E4%2B6x%5E3-12x%5E2-24%5Csqrt%7B3%7Dx-72%5C%5C)
Answer: the area of the shaded region is 5x² + 28x + 23
Step-by-step explanation:
The formula for determining the area of the rectangle is expressed as
Area = length × width
The area of the smaller rectangle is
(x - 3)(x - 1)
We would apply the distributive property by multiplying each term in one bracket by each term in the other bracket. It becomes
x² - x - 3x + 1
x² - 4x + 1
The area of the bigger rectangle is
(3x + 6)(2x + 4)
6x² + 12x + 12x + 24
6x² + 24x + 24
The area of the shaded region would be
6x² + 24x + 24 - (x² - 4x + 1)
6x² + 24x + 24 - x² + 4x - 1
6x² - x² + 24x + 4x + 24 - 1
5x² + 28x + 23
Answer:
The answer is <u>-37</u>.
Step-by-step explanation:
1) Simplify 50-2 to 48.
48 ÷ 4 - ![7^{2}](https://tex.z-dn.net/?f=7%5E%7B2%7D)
2) Simplify
to 49.
48 ÷ 4 - 49
3) Simplify 48 ÷ 4 to 12.
![12 - 49](https://tex.z-dn.net/?f=12%20-%2049)
4) Simplify.
![-37](https://tex.z-dn.net/?f=-37)
<u>Therefor, the answer is </u><u>Option C) -37</u><u>.</u>