Step-by-step explanation:
Hey there!!!
Here,
Given, A line passes through point (2,-2) and is perpendicular to the y= 5x+2.
The equation of a straight line passing through point is,

Now, put all values.

It is the 1st equation.
Another equation is;
y = 5x +2........(2nd equation).
Now, Comparing it with y = mx + c, we get;
m2=5
As per the condition of perpendicular lines,
m1×m2= -1
m1 × 5 = -1
Therefore, m2= -1/5.
Keeping the value of m1 in 1st equation.

Simplify them.



Therefore the required equation is x+5y+8= 0.
<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
I'm not following. What's the question?
Answer:
y = -7x +8
Step-by-step explanation:
The slope-intercept form of the equation of a line is ...
y = mx +b
where m represents the slope, and b represents the y-intercept. The y-intercept is the value of y when x=0. Here, you have m=-7 and b=8. Your equation is ...
y = -7x +8
Answer:
we list the number from smallest to large without for conditions like e.g 5 in hundred place and 7 in one place. therefore, 103547