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3 years ago

What is the slope of the line containing (-3, 5) and (6, -1)?

2 answers:

4 0

We can find the slope by using the formula y2-y1/x2-x1. y2 and x2 are our second y and x coordinates, meanwhile y1 and x1 are our first y and x coordinates. If we plug in our numbers, we get -1-5/6-(-3). This gives us -1-5/6+3. -1-5/6+3 is -6/9. -6/9 is equal to -2/3. The answer is B.

mario62 [17]3 years ago

3 0

Answer:

-2/3

Step-by-step explanation:

The slope of a line can be represented as $\frac{y_{2} -y_{1} }{x_{2}- x_{1} }$ where (x1, y1) and (x2, y2) are points on the line. We can substitute the points given, (-3, 5) and (6, -1), to calculate the slope:

$\frac{-1-5}{6-(-3)} =\frac{-6}{6+3} =\frac{-6}{9} =-\frac{2}{3}$

You might be interested in

Which equation is related to (squ)x+10)-1?

mihalych1998 [28]

(x + 10)² - 1

= (x² + 20x + 100) - 1

= x² + 20x + 99

None of the choices you provided are correct. Did you type in the question wrong?

8 0

2 years ago

Read 2 more answers

Deer ticks can be carriers of either Lyme disease or human granulocytic ehrlichiosis (HGE). Based on a recent study, suppose tha

san4es73 [151]

Answer:

0.2364

Step-by-step explanation:

We will take

Lyme = L

HGE = H

P(L) = 16% = 0.16

P(H) = 10% = 0.10

P(L ∩ H) = 0.10 x p(L U H)

Using the addition theorem

P(L U H) = p(L) + P(H) - P(L ∩ H)

P(L U H) = 0.16 + 0.10 - 0.10 * p(L u H)

P(L U H) = 0.26 - 0.10p(L u H)

We collect like terms

P(L U H) + 0.10P(L U H) = 0.26

This can be rewritten as:

P(L U H)[1 +0.1] = 0.26

Then we have,

1.1p(L U H) = 0.26

We divide through by 1.1

P(L U H) = 0.26/1.1

= 0.2364

Therefore

P(L ∩ H) = 0.10 x 0.2364

The probability of tick also carrying lyme disease

P(L|H) = p(L ∩ H)/P(H)

= 0.1x0.2364/0.1

= 0.2364

3 0

2 years ago

A production process is known to produce a particular item in such a way that 5 percent of these are defective. If two items are

IRINA_888 [86]

Answer:

0.0025 = 0.25% probability that both are defective

Step-by-step explanation:

For each item, there are only two possible outcomes. Either they are defective, or they are not. Items are independent of each other. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

5 percent of these are defective.

This means that $p = 0.05$

If two items are randomly selected as they come off the production line, what is the probability that both are defective

This is P(X = 2) when n = 2. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{2,2}.(0.05)^{2}.(0.95)^{0} = 0.0025$

0.0025 = 0.25% probability that both are defective

4 0

2 years ago

ASHA 777 [7]

Answer:

Step-by-step explanation:

Vertex A of the triangle ABC when rotated by 90° counterclockwise about the origin,

Rule to be followed,

A(x, y) → P(-y, x)

Therefore, A(1, 1) → P(-1, 1)

Similarly, B(3, 2) → Q(-2, 3)

C(2, 5) → R(-5, 2)

Triangle given in second quadrant will be the triangle PQR.

If the point P of triangle PQR is reflected across a line y = x,

Rule to be followed,

P(x, y) → X(y, x)

P(-1, 1) → X(1, -1)

Similarly, Q(-2, 3) → Y(3, -2)

R(-5, 2) → Z(2, -5)

Therefore, triangle given in fourth quadrant is triangle XYZ.

6 0

3 years ago

Answer choices:

vova2212 [387]

A and T are points. On their own, they cannot define a line. So we can rule out choice A

WCR and TRA are angles. For any triple the points do not fall on the same straight line. So we cannot define any lines here. This crosses off choice B

Choice C is the answer because WC does define a line. We only need two points to form a line. Similarly CR does the same job. We draw a line marker with two arrows at each end to be placed over the letters to indicate "line".

Choice D is similar to choice D; however, it is not the answer because WT is the same line as WC. In other words, WC = WT. We haven't named a new line at all. We're simply repeating ourselves.

6 0

3 years ago