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OLga [1]
3 years ago
12

ASAP I NEED AN ANSWER TO THIS PROBLEM

Mathematics
1 answer:
mihalych1998 [28]3 years ago
5 0
Subtract them :)
2020 - 2012 is 8
2017 - 2015 is 2
8 dived by 2 is (4)
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A sample of 64 was taken from a population, with the mean of the sample being 119 and the standard deviation of the sample being
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We have the sample size, sample mean and the sample standard deviation. Since the population standard deviation is not know, we will use t-distribution to find the confidence interval.

The critical t value for 95% confidence interval and 63 degrees of freedom is 1.998.

The 95% confidence for the population mean will be:

(119-1.998 *\frac{16}{ \sqrt{64} } ,119+1.998 *\frac{16}{ \sqrt{64} }) \\  \\ 
=(115.004, 122.996) \\ \\=(115,123)

Thus, the 95% confidence interval for the population mean will be (115,123)

So, option A is the correct answer
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Answer:

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x = - 20/2

x = - 10

m\angle A = (x +53)\degree \\\\m\angle A = (-10 +53)\degree \\\\m\angle A = 43\degree \\\\

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