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OLga [1]
3 years ago
12

ASAP I NEED AN ANSWER TO THIS PROBLEM

Mathematics
1 answer:
mihalych1998 [28]3 years ago
5 0
Subtract them :)
2020 - 2012 is 8
2017 - 2015 is 2
8 dived by 2 is (4)
You might be interested in
Dos numeros naturales se diferencian en 7 unidades y la suma de sus cuadrados es 289
NeTakaya

Answer:

15 y 8

Step-by-step explanation:

y = x - 7

x² + y² = 289

sustituir: x² + (x - 7)² = 289

distribuir: x² + x² - 14x + 49 = 289

sustraer + simplificar: 2x² - 14x - 240 = 0

dividir: x² - 7x - 120 = 0

x² - 15x + 8x - 120 = 0

(x - 15)(x + 8) = 0

x = 15, x = -8 --> x ≠ -8 porque -8 no es naturales

sustituir: y = 15 - 7

simplificar: y = 8

6 0
3 years ago
Please Help FAST
Aneli [31]

Answer:

Step-by-step explanation:

1) 2x -y = 1 -------1

3x - y = -6 ------2

Subtract eqn 2 from eqn 1

-x = 1--6 = 7

x = -7

Put x= -7 in eqn 1

2*-7-y = 1

-14-y = 1

- y = 15

y = -15

2) 4x +2y = 10------1

y = 4x + 2--------2

Put eqn 2 in eqn 1

4x + 2 ( 4x+ 2) = 10

4x + 8x + 4 = 10

12x = 6

x = 6/12 = 1/2

Put x = 1/2 in eqn 2

y = 4* 1/2 + 2= 2 + 2

= 4

3) 6x - y = 2------1

y = 3x + 4---------2

Put eqn 2 in eqn 1

6x - (3x +4) = 2

6x - 3x - 4 = 2

3x = 6

x = 2

y = 3*2 + 4 = 6 + 4

= 10

6 0
3 years ago
Fill in the blanks in the list.
kolbaska11 [484]
1. shape
2.angles
3.sides
6 0
3 years ago
Find m<1 then m<2. State the theroms or prostulates that justify your answers​
ki77a [65]

Answer:

fffgfdfgee

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
~**Will mark brainliest **~<br> For the correct answers to all three questions
aleksandr82 [10.1K]

a)

\dfrac{42}{65}\cdot\dfrac{25}{36}\cdot\dfrac{26}{49}=\dfrac{2\cdot3\cdot7}{5\cdot13}\cdot\dfrac{5\cdot5}{2\cdot2\cdot3\cdot3}\cdot\dfrac{2\cdot13}{7\cdot7}=\dfrac{7}{13}\cdot\dfrac{5}{2\cdot3}\cdot\dfrac{2\cdot13}{7\cdot7}=\\\\\\=\dfrac{1}{1}\cdot\dfrac{5}{2\cdot3}\cdot\dfrac{2}{7}=\dfrac{5}{3}\cdot\dfrac{1}{7}=\dfrac{5}{21}

b)

\dfrac{21}{32}\cdot\dfrac{39}{120}\cdot\dfrac{40}{65}=\dfrac{21}{32}\cdot\dfrac{3\cdot13}{2\cdot2\cdot2\cdot3\cdot5}\cdot\dfrac{2\cdot2\cdot2\cdot5}{5\cdot13}=\\\\\\=\dfrac{3\cdot7}{32}\cdot\dfrac{13}{2\cdot2\cdot2\cdot5}\cdot\dfrac{2\cdot2\cdot2}{13}=\dfrac{21}{32}\cdot\dfrac{1}{5}\cdot\dfrac{1}{1}=\dfrac{21}{160}

c)

\dfrac{15}{90}\cdot\dfrac{36}{75}\cdot\dfrac{27}{42}=\dfrac{3\cdot5}{2\cdot3\cdot3\cdot5}\cdot\dfrac{2\cdot2\cdot3\cdot3}{3\cdot5\cdot5}\cdot\dfrac{3\cdot3\cdot3}{2\cdot3\cdot7}=\\\\\\=\dfrac{1}{2\cdot3}\cdot\dfrac{2\cdot2\cdot3}{5\cdot5}\cdot\dfrac{3\cdot3}{2\cdot7}=\dfrac{1}{1}\cdot\dfrac{2}{5\cdot5}\cdot\dfrac{3\cdot3}{2\cdot7}=\dfrac{1}{25}\cdot\dfrac{9}{7}=\dfrac{9}{175}

6 0
3 years ago
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