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erma4kov [3.2K]
3 years ago
6

Can someone help me please? thank you

Physics
1 answer:
stepan [7]3 years ago
4 0
....................
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4. A 70.0 kg boy and a 45.0 kg girl use an elastic rope while engaged in a tug-of-war on an icy,
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Answer:

a_1 = 1.446m/s^2

Explanation:

Given

m_1 = 70.0kg -- Mass of the boy

m_2 = 45.0kg -- Mass of the girl

a_2 = 2.25m/s^2 -- Acceleration of the girl towards the boy

Required

Determine the acceleration of the boy towards the girl (a_1)

From the question, we understand that the surface is frictionless. This implies that the system is internal and the relationship between the given and required parameters is:

m_1 * a_1 = m_2 * a_2

Substitute values for m_1, m_2 and a_2

70.0 * a_1 = 45.0 * 2.25

Make a_1 the subject

\frac{70.0 * a_1}{70.0} = \frac{45.0 * 2.25}{70.0}

a_1 = \frac{45.0 * 2.25}{70.0}

a_1 = \frac{101.25}{70.0}

a_1 = 1.446m/s^2

<em>Hence, the acceleration of the boy towards the girl is 1.446m/s^2</em>

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The secondary coil of a step-up transformer provides the voltage that operates an electrostatic air filter. The turns ratio of t
Sphinxa [80]

Answer:

The power consumed by the air filter is 9.936 watts      

Explanation:

It is given that, the secondary coil of a step-up transformer provides the voltage that operates an electrostatic air filter.

Turn ratio of the transformer, \dfrac{N_s}{N_p}=\dfrac{46}{1}

Voltage of primary coil, V_p=120\ V

Current in the secondary coil, I_s=1.8\times 10^{-3}\ A

The power consumed by the air filter is :

P_s=I_s\times V_s...........(1)

For a transformer, \dfrac{N_s}{N_p}=\dfrac{V_s}{V_p}

So, P_s=I_s\times (\dfrac{N_s}{N_p})\times V_p

P_s=1.8\times 10^{-3}\times (\dfrac{46}{1})\times 120

P_s=9.936\ Watts

So, the power consumed by the air filter is 9.936 watts. Hence, this is the required solution.                

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4 years ago
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