$F = k\frac{q_1q_1}{ {d}^{2} } \\ = 9.0 \times {10}^{9} (N {m}^{2} {C}^{ - 2}) \frac{30 \times {10}^{ - 6} (C)5.0 \times {10}^{ - 6} (C)}{ {0.3}^{2} } N$

3 0

3 years ago

A truck tire rotates at an initial angular speed of 21.5 rad/s. The driver steadily accelerates, and after 3.50 s the tire's ang

erma4kov [3.2K]

Given:

initial angular speed, $\omega _{i}$ = 21.5 rad/s

final angular speed, $\omega _{f}$ = 28.0 rad/s

time, t = 3.50 s

Solution:

Angular acceleration can be defined as the time rate of change of angular velocity and is given by:

$\alpha = \frac{\omega_{f} - \omega _{i}}{t}$

Now, putting the given values in the above formula:

$\alpha = \frac{28.0 - 21.5}{3.50}$

$\alpha = 1.86 m/s^{2}$

Therefore, angular acceleration is:

$\alpha = 1.86 m/s^{2}$

5 0

3 years ago

Force causes __________ dimensional objects to rotate

padilas [110]

Forces may cause a three-dimensional object to rotate. These forces are called "orthogonal force vectors" which composes of a horizontal component and vertical component, which hand-in-hand, help a body to rotate in accordance with the force applied on a part of its surface.

3 0

4 years ago

A 2.00 m-long 6.00 kg ladder pivoted at the top hangs down from a platform at the circus. A 42.0 kg trapeze artist climbs to a p

prisoha [69]

Answer:

f= 0.48 s⁻¹

Explanation:

Given that

Mass of the ladder ,m= 6 kg

L= 2 m

Mass of artist ,M= 42 kg

The total moment of inertia of the both ladder and artist ,I