There are 15 animals in a barn. These animals are horses and chickens. There are 44

The length of a triangel is three times its with.if the perimiter is at its most 112 centemeters,witch is the greates possible v

iris [78.8K]

I am assuming you do not mean The length of a triangle and you mean The length of a rectangle because the answer you given are the formula for the perimeter of a rectangle. With that said, the answer is D.2w+2*(3w)112

The perimeter of a rectangle can be found by the following equation:

2L + 2W = P
OR
P = 2L + 2W
The equation P = 2L + 2W is read perimeter = 2 times Length + 2 times width

The Question:
The length of a rectangle is three times its width.if the perimeter is at its most 112 centimeters ,which is the greatest possible value of the the width.

The length of a rectangle
This means the perimeter

is
The word is means to use an equal sign

three times its width
This means 3 times w or 3w
The w = width

perimeter is at its most 112
This means <=
<= means less than or equal to

Ok so lets look at our equation

2L + 2W = P
2w + 2(3w) <= 112

5 0

2 years ago

What is 13x+15= 11x -25 also expalin plz

kari74 [83]

$13x+15=11x-25 \\ \\ 13x-11x=-25-15 \\\\ 2x=-40 \\\\ \boxed{x=-\frac{40}{2}=-20}$

You pass the free terms wich don't contain 'x' in the othe part of the equal with changed signe ans the same for the terms wich contain x.

8 0

3 years ago

Can someone help me w this plz

melomori [17]

A.
If you solve it all out you get f(x)= -4x^2 -56x-202

5 0

2 years ago

Read 2 more answers

Look at the figures. How can you prove these triangles are congruent?

Novosadov [1.4K]

Answer:

A. $\Delta ABC\cong \Delta DEF$ by the SAS postulate.

Step-by-step explanation:

We have been two triangles. We are asked to determine the theorem by which both triangles could be proven congruent.

We can see that side DF of triangle DEF is equal to side AC of triangle ABC.

We can also see that side BC of triangle ABC is equal to side EF of triangle DEF.

The including angle between sides AC and BC of triangle ABC is equal to the including angle between sides DF and EF of triangle DEF.

Since both triangles have two sides and their included angles equal, therefore, triangle ABC is congruent to triangle DEF by SAS (Side-Angle-Side) congruence and option A is the correct choice.

5 0

3 years ago

A Martian couple has children until they have 2 males (sexes of children are independent). Compute the expected number of childr

Ne4ueva [31]

Answer:

a) 6

b) 4

c) 3

Step-by-step explanation:

Let p be the probability of having a female Martian, and of course, 1-p the probability of having a male Martian.

To compute the expected total number of trials before 2 males are born, imagine an experiment simulating the fact that 2 males are born is performed n times.

Let ak be the number of trials performed until 2 males are born in experiment k. That is,

a1= number of trials performed until 2 males are born in experiment 1

a2= number of trials performed until 2 males are born in experiment 2

and so on.

If a1 + a2 + … + an = N

we would expect Np females.

Since the experiment was performed n times, there 2n males (recall that the experiment stops when 2 males are born).

So we would expect 2n = N(1-p), or

N/n = 2/(1-p)

But N/n is the average number of trials per experiment, that is, the expectation.

We have then that the expected number of trials before 2 males are born is 2/(1-p) where p is the probability of having a female.

a)

Here we have the probability of having a male is half as likely as females. So

1-p = p/2 hence p=2/3

The expected number of trials would be

2/(1-2/3) = 2/(1/3) =6

This means the couple would have 6 children: 4 females (the first 4 trials) and 2 males (the last 2 trials).

b)

Here the probability of having a female = probability of having a male = 1/2

The expected number of trials would be

2/(1/2) = 4

This means the couple would have 4 children: 2 females (the first 2 trials) and 2 males (the last 2 trials).

c)

Here, 1-p = 2p so p=1/3

The expected number of trials would be

2/(1-1/3) = 2/(2/3) = 6/2 =3

This means the couple would have 3 children: 1 female (the first trial) and 2 males (the last 2 trials).

5 0

3 years ago