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almond37 [142]
3 years ago
6

Marcus White has just been promoted to a manager. To give him access to the files that he needs, you make his user account a mem

ber of the Managers group, which has access to a special shared folder. Later that afternoon, Marcus tells you that he is still unable to access the files reserved for the Managers group. What should you do
Computers and Technology
1 answer:
Svetach [21]3 years ago
4 0

Answer:

log off of his account and log back in

Explanation:

The first thing that Marcus should do would be to log off of his account and log back in. This is so that the new changes to his permissions can take effect. This should solve his problem and grant him access to all the permissions available in the Managers Group. If this does not work, then it is most likely that he is still in the previous group which has the Manager level permissions blocked. In this case he would need to leave the previous group that he is in because the blocking permissions overrides the access allowed from the Managers group.

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Explain the difference between IPv4 and IPv6.
Leni [432]

Answer:

The Internet Protocol version 4 (IPv4) is a protocol for use on packet-switched Link Layer networks (e.g. Ethernet). IPv4 provides an addressing capability of approximately 4.3 billion addresses. The Internet Protocol version 6 (IPv6) is more advanced and has better features compared to IPv4.

Explanation:

Without IP addresses, computers would not be able to communicate and send data to each other. It's essential to the infrastructure of the web. A: IPv6 is the sixth revision to the Internet Protocol and the successor to IPv4

5 0
3 years ago
Its Inventiveness, uncertainty and futuristic ideas typically deals with science technology, what is it?
Margarita [4]

Answer:

It disrupt the established social contract, in the same way that invasive species do in natural ecosystems.

Explanation:

8 0
3 years ago
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A scientific question may lead to a(n) , which can be tested.
kari74 [83]
A hypothesis or educated guess
6 0
4 years ago
Read 2 more answers
1) differentiate between Tittle and caption
Yakvenalex [24]

Answer:

The difference and the steps to insert media in the project can be defined as follows:

Explanation:

Title:

The title is a document, that defines the object that is legally operated.  

Caption:

The Caption is also known as the title or the heading, which described the words on a screen, that conveys the message, that is being said.

Difference:

  • The titles will be assigned to the starting of the clip,  that selects, and charges will be applied to the project at the end.  
  • The caption may also be applied as a text to a specific clip for the reason.

Step to insert any media in the project:

  • Choose the preferred location to insert your media.  
  • Tap on the top of the insert Tab.      
  • Choose the desired media form.  
  • after selecting your desired media, click on the insert button, at this, the media will be inserted.
3 0
3 years ago
Hello, my first time being here and I'm returning back from college and I'm now studying Java in college but I was stuck doing t
KengaRu [80]

Answer:

import java.time.LocalDate;

class TestWedding {

 public static void main(String[] args) {

   Person man1 = new Person("John", "Doe", LocalDate.parse("1990-05-23"));

   Person woman1 = new Person("Jane", "Something", LocalDate.parse("1995-07-03"));

   Person man2 = new Person("David", "Johnson", LocalDate.parse("1991-04-13"));

   Person woman2 = new Person("Sue", "Mi", LocalDate.parse("1997-12-01"));

   Couple cpl1 = new Couple(man1, woman1);

   Couple cpl2 = new Couple(man2, woman2);

   Wedding wed1 = new Wedding(cpl1, "Las Vegas", LocalDate.parse("2020-09-12"));

   Wedding wed2 = new Wedding(cpl2, "Hawaii", LocalDate.parse("2021-01-02"));  

   displayDetails(wed1, wed2);

 }

 public static void displayDetails(Wedding w1, Wedding w2) {

   System.out.println(w1.toString());

   System.out.println(w2.toString());

 }

}

---------------------------

class Couple {

 private Person person1;

 private Person person2;

 public Couple(Person p1, Person p2) {

   person1 = p1;

   person2 = p2;

 }

 public String toString() {

   return person1.toString() + " and " + person2.toString();

 }

}

----------------------------

import java.time.LocalDate;

import java.time.format.DateTimeFormatter;

class Person {

 private String firstName;

 private String lastName;

 private LocalDate birthDate;

 public Person(String first, String last, LocalDate bdate) {

   firstName = first;

   lastName = last;

   birthDate = bdate;

 }

 public String getFirstName() {

   return firstName;

 }

 public String toString() {

   DateTimeFormatter formatter = DateTimeFormatter.ofPattern("LLLL dd, yyyy");

   return String.format("%s %s born %s", this.firstName, this.lastName, birthDate.format(formatter));

 }

}

------------------------------------

import java.time.LocalDate;

import java.time.format.DateTimeFormatter;

class Wedding {

 private Couple couple;

 private String location;

 private LocalDate weddingDate;

 public Wedding(Couple c, String loc, LocalDate wDate) {

   couple = c;

   location = loc;

   weddingDate = wDate;

 }

 public String getLocation() {

       return this.location;

 }

 public String toString() {

   DateTimeFormatter formatter = DateTimeFormatter.ofPattern("LLLL dd, yyyy");

   return  

     couple.toString() +  

     " are getting married in " + location + " on "+

     weddingDate.format(formatter);

 }

}

Explanation:

I used overrides of toString to let each object print its own details. That's why this solution doesn't really require any getters. I implemented some to show how it's done, but you'll have to complete it. The solution shows how to think in an OO way; ie., let every class take care of its own stuff.

6 0
4 years ago
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